Bunuel wrote:
A case contains c cartons. Each carton contains b boxes, and each box contains 100 paper clips. How many paper clips are contained in 2 cases?
(A) 100bc
(B) 100b/c
(C) 200bc
(D) 200b/c
(E) 200/bc
Bunuel has already demonstrated an algebraic approach, so let's try solving it by picking some numbers (aka using the INPUT-OUTPUT approach).
Let b =
3 and c =
5So, a case contains
5 cartons. Each carton contains
3 boxes, and each box contains 100 paper clips.
So, the number of paper clips in 1 case = (100)(
5)(
3) = 1500
How many paper clips are contained in 2 cases?The number of paper clips in 2 cases =
3000So, we're looking for the answer choice so that when we INPUT b =
3 and c =
5, we get an OUTPUT of
3000Now check the answer choices:
(A) 100(
3)(
5) =
1500 ELIMINATE
(B) 100(
3)/(
5) =
60 ELIMINATE
(C) 200(
3)(
5) =
3000 KEEP!!
(D) 200(
3)/(
5) =
120 ELIMINATE
(E) 200/(
3)(
5) =
200/15 ELIMINATE
Answer: C
RELATED RESOURCESAs you can see, Bunuel and I have demonstrated the two methods (Algebraic and Input-Output) for solving a question type I call Variables in the Answer Choices.
If you'd like more information on these approaches, we have some free videos:
Cheers,
Brent
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