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# A CEO is building an extra-wide garage in which to park his

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Senior Manager
Joined: 10 Jul 2013
Posts: 330

Kudos [?]: 419 [0], given: 102

A CEO is building an extra-wide garage in which to park his [#permalink]

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21 Aug 2013, 17:56
00:00

Difficulty:

45% (medium)

Question Stats:

58% (01:19) correct 42% (00:48) wrong based on 26 sessions

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A CEO is building an extra-wide garage in which to park his limousines. The garage is x feet wide, and at least 2 feet of space is required between each two cars and between the cars and the walls. Will all 9 limousines fit in the garage?

(1) The average width of the limousines is the square root of x.
(2) x = 100.
[Reveal] Spoiler: OA

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Asif vai.....

Kudos [?]: 419 [0], given: 102

Math Expert
Joined: 02 Sep 2009
Posts: 41908

Kudos [?]: 129394 [0], given: 12197

Re: A CEO is building an extra-wide garage in which to park his [#permalink]

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22 Aug 2013, 02:48
Asifpirlo wrote:
A CEO is building an extra-wide garage in which to park his limousines. The garage is x feet wide, and at least 2 feet of space is required between each two cars and between the cars and the walls. Will all 9 limousines fit in the garage?

(1) The average width of the limousines is the square root of x.
(2) x = 100.

Some assumptions to be made in this question...

When we combine we get that the width of limousines is 10 meters. Thus 9 limousines will need 9*10=90 meters, plus the additional space required between each two cars and between the cars and the walls. The sum will be more than 100 meters. So, the answer is NO. Sufficient.

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Kudos [?]: 129394 [0], given: 12197

Senior Manager
Joined: 24 Aug 2009
Posts: 498

Kudos [?]: 841 [0], given: 276

Schools: Harvard, Columbia, Stern, Booth, LSB,
Re: A CEO is building an extra-wide garage in which to park his [#permalink]

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22 Aug 2013, 03:10
Asifpirlo wrote:
A CEO is building an extra-wide garage in which to park his limousines. The garage is x feet wide, and at least 2 feet of space is required between each two cars and between the cars and the walls. Will all 9 limousines fit in the garage?
(1) The average width of the limousines is the square root of x.
(2) x = 100.

x = 9 (Average width of Limo) + Min [10 (2)] -----(1)
10 because 9 cars will have 8 gaps & 2 gaps for extreme ends (between wall & car)

Statement 1
x = 9 $$\sqrt{x}$$ + Min [10 (2)]
Still we cant solve the equation as we don't know the value of x
Thus insufficient

Statement 2
100 = 9 (Average width of Limo) + Min [10 (2)]
Still we cant solve the equation as we don't know the value of "Average width of Limo"
Thus insufficient

Statement 1&2
100 = 9 $$\sqrt{100}$$ + Min [10 (2)]
100 = 9 (10) + Min [10 (2)]
100 = Min 110
This clearly shows the garage won't be able to hold all the 9 limos
Thus Sufficient

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Kudos [?]: 841 [0], given: 276

Re: A CEO is building an extra-wide garage in which to park his   [#permalink] 22 Aug 2013, 03:10
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