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# A certain bakery ran a promotion code: a customer can buy x

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Joined: 12 Oct 2011
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GMAT 1: 700 Q48 V37
GMAT 2: 720 Q48 V40
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Kudos [?]: 211 [3] , given: 23

A certain bakery ran a promotion code: a customer can buy x [#permalink]

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04 Apr 2012, 05:47
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Difficulty:

65% (hard)

Question Stats:

61% (04:15) correct 39% (02:28) wrong based on 149 sessions

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A certain bakery ran a promotion code: a customer can buy x donuts for the regular price of $15 total and get 3 donuts free. If the donut price per dozen during the promotion is$2 less than the normal donut price per dozen, what is x?

A. 15
B. 18
C. 21
D. 25
E. 30
[Reveal] Spoiler: OA
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Kudos [?]: 106133 [5] , given: 11607

Re: A certain bakery ran a promotion code: a customer can buy x [#permalink]

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04 Apr 2012, 06:07
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BN1989 wrote:
A certain bakery ran a promotion code: a customer can buy x donuts for the regular price of $15 total and get 3 donuts free. If the donut price per dozen during the promotion is$2 less than the normal donut price per dozen, what is x?

A. 15
B. 18
C. 21
D. 25
E. 30

The promotion price per donut is $$\frac{15}{x+3}$$, thus the promotion price per dozen is $$12*\frac{15}{x+3}$$;

The regular price per donut is $$\frac{15}{x}$$, thus the regular price per dozen is $$12*\frac{15}{x}$$;

We are told that the promotion price per dozen is $2 less than the normal donut price per dozen: $$12*\frac{15}{x+3}+2=12*\frac{15}{x}$$ --> $$\frac{180}{x+3}+2=\frac{180}{x}$$. At this point it's better to substitute the values rather than solve for x. Answer choice A, 15, works. Answer: A. _________________ Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7374 Location: Pune, India Followers: 2288 Kudos [?]: 15111 [3] , given: 224 Re: A certain bakery ran a promotion code: a customer can buy x [#permalink] ### Show Tags 15 Jan 2013, 20:42 3 This post received KUDOS Expert's post BN1989 wrote: A certain bakery ran a promotion code: a customer can buy x donuts for the regular price of$15 total and get 3 donuts free. If the donut price per dozen during the promotion is $2 less than the normal donut price per dozen, what is x? A. 15 B. 18 C. 21 D. 25 E. 30 Responding to a pm: The wording of the question is such that it is normal to read it twice to understand it well. Promotion Code: a customer can buy x donuts for the regular price of$15 total and get 3 donuts free

This tells us two things:
The regular price of x donuts is $15. So regular price per donut is 15/x In the promotion, you get 3 donuts free with x donuts. So promotion price per donut is 15/(x+3) For a dozen, the promotion price is$2 less. So per donut, the promotion price is $2/12 less. 15/x - 2/12 = 15/(x+3) Now try to plug in values of x from the options. The equation holds if x = 15 If you face problems making equations in word problems, the issue is practice. You might struggle with 50 advanced word problem questions but then, when you go on to question no. 51, the equation will be more intuitive. Also, don't give up too soon while trying to solve a question (not talking about the actual or simulated tests here). Put in a good 10-15 mins to figure it out on your own before you finally give up and check out the solution. If you are able to solve it on your own, it will give you insight you will never forget. To practice advanced word problems, you can check out the Veritas advanced word problems book. It will certainly help you get a handle on such questions. _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Re: A certain bakery ran a promotion code: a customer can buy x [#permalink]

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25 Feb 2014, 10:55
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: A certain bakery ran a promotion code: a customer can buy x [#permalink]

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25 Feb 2014, 17:49
should have plugged in (as per the above advice)...

12[[(15/(X+3)]-[15/x]]=2
...
x^2+3x-270=0
...after doing a prime factorization of 270....
(x-15)(x+18)=0
x=15
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Re: A certain bakery ran a promotion code: a customer can buy x [#permalink]

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23 Mar 2015, 03:36
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: A certain bakery ran a promotion code: a customer can buy x [#permalink]

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04 Dec 2016, 04:54
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: A certain bakery ran a promotion code: a customer can buy x   [#permalink] 04 Dec 2016, 04:54
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