GMAT Question of the Day: Daily via email | Daily via Instagram New to GMAT Club? Watch this Video

It is currently 02 Jun 2020, 01:03

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

A certain building has only 2-room and 3-room apartments to rent. If

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 64133
A certain building has only 2-room and 3-room apartments to rent. If  [#permalink]

Show Tags

New post 23 Jul 2019, 07:00
00:00
A
B
C
D
E

Difficulty:

  75% (hard)

Question Stats:

57% (01:50) correct 43% (02:19) wrong based on 232 sessions

HideShow timer Statistics

A certain building has only 2-room and 3-room apartments to rent. If the range of the rental fees of all the apartments in the building is $1,000 and the range of the rental fees for 3-room apartments is $600, what is the range of the rental fees for 2-room apartments?

(1) The lowest rental fee for a 3-room apartment in the building is $200 more than the highest rental fee for a 2-room apartment in the building.
(2) The lowest rental fee for a 2-room apartment is $800 in the building.

 

This question was provided by Math Revolution
for the Game of Timers Competition

 


_________________
Manager
Manager
User avatar
G
Joined: 28 Jan 2019
Posts: 76
Location: Peru
GMAT 1: 640 Q49 V29
Premium Member
A certain building has only 2-room and 3-room apartments to rent. If  [#permalink]

Show Tags

New post Updated on: 23 Jul 2019, 18:03
2
From the statement we have the following:

Range is Max - Min = 1000

Range for 3 - room = Max3 - Min3 =600


From (1) The lowest rental fee for a 3-room apartment in the building is $200 more than the highest rental fee for a 2-room apartment in the building, we have that:

Min3 - Max2 = 200, then the range will have to be Max3 - Min2 =1000

but since we have Max3 - Min3 =600, Min3-Max2 = 200, the difference between Max2 - Min 2 must be 200 in order to complete the range.

So, sufficient.

From (2) The lowest rental fee for a 2-room apartment is $800 in the building, we have that:


We have the lowest rental fee for a 2 room but we do not anything about the max value of 2, so clearly insufficient.

(A) is our answer

Originally posted by Mizar18 on 23 Jul 2019, 07:47.
Last edited by Mizar18 on 23 Jul 2019, 18:03, edited 1 time in total.
Manager
Manager
User avatar
G
Joined: 05 Mar 2017
Posts: 205
Location: India
Concentration: General Management, Marketing
GPA: 3.6
WE: Marketing (Hospitality and Tourism)
Reviews Badge
Re: A certain building has only 2-room and 3-room apartments to rent. If  [#permalink]

Show Tags

New post 23 Jul 2019, 07:31
1
A certain building has only 2-room and 3-room apartments to rent. If the range of the rental fees of all the apartments in the building is $1,000 and the range of the rental fees for 3-room apartments is $600, what is the range of the rental fees for 2-room apartments?

This is an easy question.
Let's analyze the stem first.
Lets LABEL
2 room Lowest X
2 room Highest Y
3 room Lowest Z
3 room Highest T

Its is given to use that the range combined is 1000
and T-Z = 600 ....1

We are looking for Y - X

Let's analyze the statements now.

(1) The lowest rental fee for a 3-room apartment in the building is $200 more than the highest rental fee for a 2-room apartment in the building.
This gives us Z = Y +200 ....2
This tells us that the highest of the 2 room is still lower than the lowest of the 3 room. Which helps us establish that T - X = 1000 ....3
Y - X = (Puting 2 & 3 here ) Z-200 - T+ 1000 = Z-T +800 . Now put 1 here =T- 600- T + 800 = 200 is the answer.

Hence this statement is correct.


(2) The lowest rental fee for a 2-room apartment is $800 in the building.
This statement is insufficient.

Hence the answer is A.
CEO
CEO
User avatar
V
Joined: 03 Jun 2019
Posts: 2921
Location: India
GMAT 1: 690 Q50 V34
WE: Engineering (Transportation)
Premium Member Reviews Badge CAT Tests
Re: A certain building has only 2-room and 3-room apartments to rent. If  [#permalink]

Show Tags

New post 23 Jul 2019, 08:03
1
1
A certain building has only 2-room and 3-room apartments to rent. If the range of the rental fees of all the apartments in the building is $1,000 and the range of the rental fees for 3-room apartments is $600, what is the range of the rental fees for 2-room apartments?

(1) The lowest rental fee for a 3-room apartment in the building is $200 more than the highest rental fee for a 2-room apartment in the building.
(2) The lowest rental fee for a 2-room apartment is $800 in the building.

Please see the solution below in image.

IMO A
Attachments

2019-07-23_213200.jpg
2019-07-23_213200.jpg [ 781.54 KiB | Viewed 1903 times ]


_________________
Kinshook Chaturvedi
Email: kinshook.chaturvedi@gmail.com
Manager
Manager
avatar
B
Joined: 24 Jun 2019
Posts: 66
A certain building has only 2-room and 3-room apartments to rent. If  [#permalink]

Show Tags

New post Updated on: 23 Jul 2019, 20:45
1
A certain building has only 2-room and 3-room apartments to rent. If the range of the rental fees of all the apartments in the building is $1,000 and the range of the rental fees for 3-room apartments is $600, what is the range of the rental fees for 2-room apartments?

I found it easy to solve by imagining highest and lowest rental fees of 2 and 3 room apartments to be points on a number line and RANGE as DISTANCE between 2 points.

A_____B______X______Y

A = LOWEST FEES (dont know 2 room or 3 room)
Y = HIGHEST FEES (dont know 2 room or 3 room)
B and X are Lowest or Highest of 2 room or 3 room, we dont know which is which.

Distance AY = 1000
Distance of 3 room highest and lowes is 600.... But we dont know which 2 points they are on the number line

(1) The lowest rental fee for a 3-room apartment in the building is $200 more than the highest rental fee for a 2-room apartment in the building.

Lowest of 3 room is higher than highest of 2 room.... SO ALL 2 ROOMS are LOWER than 3 rooms

A = Lowest 2 room
B = Highest 2 room
X = Lowest 3 room
Y = Highest 3 room

FIND AB

AY = 1000... because total range is 1000
BX = 200...... because lowest 3 room is 200 more than highest 2 room
XY = 600.... because 3 room range is 600

AB = 1000 - 600 - 200 = 200

(1) IS SUFFICIENT

(2) The lowest rental fee for a 2-room apartment is $800 in the building.

Lowest 2 room is 800, BUT, we dont know if 800 is A, or B, or X... it could be either of the 3.

We also dont know which one is Highest 2 room, so what do we find the distance between??

(2) IS NOT SUFFICIENT


ANSWER: A - 1 Alone is sufficient

Originally posted by Vinit1 on 23 Jul 2019, 08:21.
Last edited by Vinit1 on 23 Jul 2019, 20:45, edited 1 time in total.
GMAT Club Bot
A certain building has only 2-room and 3-room apartments to rent. If   [#permalink] 23 Jul 2019, 08:21

A certain building has only 2-room and 3-room apartments to rent. If

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne