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# A certain company's customer service department has five

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Director
Joined: 15 Aug 2005
Posts: 794

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Location: Singapore
A certain company's customer service department has five [#permalink]

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12 Oct 2005, 21:26
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A certain company's customer service department has five employees. The hourly wage for each employee ranges from \$5 an hour to \$20 an hour. Which of the following could be the average (arithmetic mean) hourly wage for the customer service employees?

1) \$7.50 an hour
2) \$9 an hour
3) \$16.75 an hour

A. 1 only
B. 2 only
C. 3 only
D. 1 and 2 only
E. 2 and 3 only
_________________

Cheers, Rahul.

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Director
Joined: 21 Aug 2005
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12 Oct 2005, 21:33
E (2 & 3 only)

Avg. can range b/w
1. Max 17 with wages 20, 20, 20, 20, 5
2. Min 8 with wages 5, 5, 5, 5, 20

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Senior Manager
Joined: 11 May 2004
Posts: 453

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Location: New York

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13 Oct 2005, 07:14
Not sure if I am reading the question correctly, but is it possible for the wages to be another value other than \$5 or \$20? Also, can we have a wage as \$7.5?

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Manager
Joined: 10 Sep 2005
Posts: 162

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15 Oct 2005, 09:04
am still nt getting this...
the avg can range max from 20,20,20,20,19 = avg 19.9 & min 5,5,5,5,6 = avg 5.2...I see all 3 as a possibility

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Senior Manager
Joined: 02 Oct 2005
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15 Oct 2005, 11:21
desiguy wrote:
Not sure if I am reading the question correctly, but is it possible for the wages to be another value other than \$5 or \$20? Also, can we have a wage as \$7.5?

Yes it is possible. However atleast one wage has to be 5 and other has to be 20. Hence it adheres to range of 5 to 20.

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Senior Manager
Joined: 02 Oct 2005
Posts: 297

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15 Oct 2005, 11:23
sushom101 wrote:
am still nt getting this...
the avg can range max from 20,20,20,20,19 = avg 19.9 & min 5,5,5,5,6 = avg 5.2...I see all 3 as a possibility

The question has given the range from 5 to 20. Hence atleast one's salary should be 5 and other should be 20. With this you would be able to calculate the min and max range of arithmetic mean and choose the answer.

Please refer to gsr/Himalaya's post as well.

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15 Oct 2005, 11:23
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