It is currently 22 Oct 2017, 23:36

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A certain football team played x games last season, of which

Author Message
TAGS:

### Hide Tags

Director
Status: Finally Done. Admitted in Kellogg for 2015 intake
Joined: 25 Jun 2011
Posts: 532

Kudos [?]: 4132 [0], given: 217

Location: United Kingdom
GMAT 1: 730 Q49 V45
GPA: 2.9
WE: Information Technology (Consulting)
A certain football team played x games last season, of which [#permalink]

### Show Tags

03 Nov 2011, 14:19
4
This post was
BOOKMARKED
00:00

Difficulty:

35% (medium)

Question Stats:

72% (01:09) correct 28% (01:21) wrong based on 364 sessions

### HideShow timer Statistics

A certain football team played x games last season, of which the team won exactly y games. If tied games were not possible, how many games did the team win last season?

(1) If the team had lost two more of its games last season, it would have won 20 percent of its games for the season.
(2) If the team had won three more of its games last season, it would have lost 30 percent of its games for the season.

[Reveal] Spoiler:
As I don't have an official answer, I will go for C. This is how I did this. Can you guys please help and let me know whether I am correct or not?

Games Lost = x-y

Considering statement 1 --> x-y+2= 0.20x
Considering statement 2 --> y+3=0.3(x-y)

Two variables and two equations and we can solve for y.
[Reveal] Spoiler: OA

_________________

Best Regards,
E.

MGMAT 1 --> 530
MGMAT 2--> 640
MGMAT 3 ---> 610
GMAT ==> 730

Kudos [?]: 4132 [0], given: 217

VP
Joined: 24 Jul 2011
Posts: 1347

Kudos [?]: 643 [1], given: 20

GMAT 1: 780 Q51 V48
GRE 1: 1540 Q800 V740
Re: A certain football team played x games last season, of which [#permalink]

### Show Tags

03 Nov 2011, 22:02
1
KUDOS
Your approach is correct, though the equations you are getting are incorrect.

Using statement 1: y-2 = 0.20x [i.e. equate the number of games won to 20% of the total games]
Using statement 2: x-y-3 = 0.30x [i.e. equate the number of games lost to 30% of the total games]

The answer should still be (C).
_________________

GyanOne | Top MBA Rankings and MBA Admissions Blog

Premium MBA Essay Review|Best MBA Interview Preparation|Exclusive GMAT coaching

Get a FREE Detailed MBA Profile Evaluation | Call us now +91 98998 31738

Kudos [?]: 643 [1], given: 20

Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7677

Kudos [?]: 17398 [6], given: 232

Location: Pune, India
Re: A certain football team played x games last season, of which [#permalink]

### Show Tags

03 Nov 2011, 23:59
6
KUDOS
Expert's post
enigma123 wrote:
A certain football team played x games last season, of which the team won exactly y games. If tied games
were not possible, how many games did the team win last season?
(1) If the team had lost two more of its games last season, it would have won 20 percent of its games for
the season.
(2) If the team had won three more of its games last season, it would have lost 30 percent of its games
for the season.

As I don't have an official answer, I will go for C. This is how I did this. Can you guys please help and let me know whether I am correct or not?

Games Lost = x-y

Considering statement 1 --> x-y+2= 0.20x
Considering statement 2 --> y+3=0.3(x-y)

Two variables and two equations and we can solve for y.

Let me add a little tip about this conclusion. Make sure that the equations you have are distinct. You can solve for y only if you have two equations. If both the equations are the same (even though they may not appear to be same), you cannot solve for y.
Check out this post for an example of this trickery: http://www.veritasprep.com/blog/2010/10 ... er-pulled/
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for \$199

Veritas Prep Reviews

Kudos [?]: 17398 [6], given: 232

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 16542

Kudos [?]: 274 [0], given: 0

Re: A certain football team played x games last season, of which [#permalink]

### Show Tags

21 Jan 2015, 11:22
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Kudos [?]: 274 [0], given: 0

EMPOWERgmat Instructor
Status: GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 9990

Kudos [?]: 3421 [0], given: 172

Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: 340 Q170 V170
Re: A certain football team played x games last season, of which [#permalink]

### Show Tags

21 Jan 2015, 14:06
Hi all,

These types of DS questions can be approached with a mix of Algebra and TESTing VALUES.

We're told that a team played X games and won Y of those games (there were NO ties). We're asked for the value of Y.

Fact 1: If the team lost 2 more games, then it would have won 20% of its games.

Algebraically, you can set up the following equation:
Y - 2 = .2X

This equation does not help you to determine the value of Y.

From a practical standpoint, you can also TEST VALUES:

IF...
X = 5 games
Y = 3 wins
Y-2 = 1 win
1/5 = 20% and the answer to the question is 3.

IF....
X = 10 games
Y = 4 wins
Y-2 = 2 wins
2/10 = 20% and the answer to the question is 4
Fact 1 is INSUFFICIENT

Fact 2: If the team won 3 more games, then it would have lost 30% of its games (meaning the team would have WON 70% of its games

Again, we can use algebra:

Y + 3 = .7X

But we have the same problem we had in Fact 1 - the equation does not help you to determine the value of Y.

Here's the proof by TESTing VALUES:

IF....
X = 10 games
Y = 4 wins
Y+3 = 7 wins
7/10 = 70% and the answer to the question is 4.

IF....
X = 20 games
Y = 11 wins
Y+3 = 14 wins
14/20 = 70% and the answer to the question is 11
Fact 2 is INSUFFICIENT

Combined, we know:
Y - 2 = .2X
Y + 3 = .7X

Here, we have a "system" of equations - with 2 variables and 2 unique equations, we CAN solve and get the value of Y.
Combined, SUFFICIENT

[Reveal] Spoiler:
C

GMAT assassins aren't born, they're made,
Rich
_________________

760+: Learn What GMAT Assassins Do to Score at the Highest Levels
Contact Rich at: Rich.C@empowergmat.com

# Rich Cohen

Co-Founder & GMAT Assassin

Special Offer: Save \$75 + GMAT Club Tests Free
Official GMAT Exam Packs + 70 Pt. Improvement Guarantee
www.empowergmat.com/

***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!***********************

Kudos [?]: 3421 [0], given: 172

CEO
Joined: 17 Jul 2014
Posts: 2604

Kudos [?]: 398 [0], given: 184

Location: United States (IL)
Concentration: Finance, Economics
GMAT 1: 650 Q49 V30
GPA: 3.92
WE: General Management (Transportation)
Re: A certain football team played x games last season, of which [#permalink]

### Show Tags

05 Nov 2015, 07:45
I tried to solve it differently, and yet..I am unsure whether my method works..
from statement 1, we have 2 more lost = 0.2x
lost game: x-y
(x-y+2)/x = 8x/10

on top we have the number of games he lost, divided by the total number of games, and get 80% of X or 8x/10
from this, we cannot solve for y

from statement 2:
y+2 = games would have been 0.3x lost
or
y+3/x = 7x/10 - since 7x/10 => 70% of games the team won
again 2 unknowns. can't solve it

1+2
well...
10x-10y+20 = 8x^2
10y+30 = 7x^2

rewrite second = 10y = 7x^2 - 30

substitute in the first equation:
10x - 7x^2 +30 +20 = 8x^2
50 = 15x^2 - 10x
divide everything by 5
10 = 3x^2 - 2x
factor a x => x(3x-2) = 10

aand here I stopped...this doesn't make any sense..

Kudos [?]: 398 [0], given: 184

Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7677

Kudos [?]: 17398 [2], given: 232

Location: Pune, India
Re: A certain football team played x games last season, of which [#permalink]

### Show Tags

05 Nov 2015, 21:25
2
KUDOS
Expert's post
mvictor wrote:
I tried to solve it differently, and yet..I am unsure whether my method works..
from statement 1, we have 2 more lost = 0.2x
lost game: x-y
(x-y+2)/x = 8x/10

on top we have the number of games he lost, divided by the total number of games, and get 80% of X or 8x/10
.

This is the problem in your analysis. why will you get 8x/10? Actually, you get 8/10

Games lost = 80% of Total Games

Games lost = (80/100) * Total Games

Games lost / Total Games = 80/100
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for \$199

Veritas Prep Reviews

Kudos [?]: 17398 [2], given: 232

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 16542

Kudos [?]: 274 [0], given: 0

Re: A certain football team played x games last season, of which [#permalink]

### Show Tags

02 Dec 2016, 07:59
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Kudos [?]: 274 [0], given: 0

Re: A certain football team played x games last season, of which   [#permalink] 02 Dec 2016, 07:59
Display posts from previous: Sort by