pzazz12 wrote:

A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ?

A. 10

B. 11

C. 12

D. 13

E. 15

Here's an approach where we

test the POSSIBLE CASES.

FACT #1: (

total cost of apples) + (

total cost of bananas) = 630 CENTS

FACT #2:

total cost of bananas is DIVISIBLE by 50, since each banana costs 50 cents.

Now let's start testing POSSIBLE scenarios.

Customer buys 1 apple.

1 apple costs

70 cents, which means the remaining

560 cents was spent on bananas.

Since

560 is NOT divisible by 50, this scenario is IMPOSSIBLE

Customer buys 2 apples.

2 apple costs

140 cents, which means the remaining

490 cents was spent on bananas.

Since

490 is NOT divisible by 50, this scenario is IMPOSSIBLE

Customer buys 3 apples.

3 apple costs

210 cents, which means the remaining

520 cents was spent on bananas.

Since

520 is NOT divisible by 50, this scenario is IMPOSSIBLE

Customer buys 4 apples.

4 apple costs

280 cents, which means the remaining

350 cents was spent on bananas.

Since

350 IS divisible by 50, this scenario is POSSIBLE

350 cents buys

7 bananas.

So, the customer buys

4 apples and

7 bananas for a total of

11 pieces of fruit

Answer:

Cheers,

Brent

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