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A certain library assesses fines for overdue books as follow

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A certain library assesses fines for overdue books as follow [#permalink]

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A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount. What is the total for a book on the fourth day it is overdue?

A. $0.60
B. $0.70
C. $0.80
D. $0.90
E. $1.00
[Reveal] Spoiler: OA

Last edited by Bunuel on 01 Apr 2012, 03:34, edited 1 time in total.
Edited the question and added the OA

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A certain library assesses fines for overdue books as follow [#permalink]

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A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount. What is the total for a book on the fourth day it is overdue?

A. $0.60
B. $0.70
C. $0.80
D. $0.90
E. $1.00

Notice that, fines are already cumulative: "For each additional day that the book is overdue, the total fine is ..."

1st day fine - 0.1
2nd day fine - 0.1*2 = 0.2 (as doubling gives lower value)
3rd day fine - 0.2*2 = 0.4 (as doubling gives lower value)
4th day fine - 0.4 + 0.3 = 0.7 (as doubling gives higher value we add 0.3 this time)

Answer: B.
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I am a little bit lost. Don't we have to add:

0.1+0.2+0.4+0.7


Thanks

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library [#permalink]

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New post 23 Sep 2010, 15:08
a certain library assess fines for overdue books as follows, on the first day that book is overdue , the total fine is 0.10. for each additional day that is overdue , the total fine is either inc by .30 or doubled, whichever results in lesser amount. What is the total fine for a book on the fourth day it is over due?
.60
.70
.80
.90
1.00.
I am getting .90 answer. my Reasoning is as follows
1(day) .10
2(day) .20 ( 2(.10)= .20 or.30 ,lesser amount .20)
3(day) .30 (2(.20)= .40 or .30, lesser amt= .30)
4(day) .30 (2(.30) =.60 or .30, lesser amount = .30)
total = .90. I dont know what am i missing?

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TomB wrote:
a certain library assess fines for overdue books as follows, on the first day that book is overdue , the total fine is 0.10. for each additional day that is overdue , the total fine is either inc by .30 or doubled, whichever results in lesser amount. What is the total fine for a book on the fourth day it is over due?
.60
.70
.80
.90
1.00.
I am getting .90 answer. my Reasoning is as follows
1(day) .10
2(day) .20 ( 2(.10)= .20 or.30 ,lesser amount .20)
3(day) .30 (2(.20)= .40 or .30, lesser amt= .30)
4(day) .30 (2(.30) =.60 or .30, lesser amount = .30)
total = .90. I dont know what am i missing?


First of all you made an error calculating 4th day:
4th day fine - 0.4+0.3=0.7 (as doubling gives higher value we add 0.3 this time)

Next you should't add up fines as they are already cumulative: "For each additional day that the book is overdue, the total fine is ..."
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Re: PS question: need help [#permalink]

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satishreddy wrote:
A certain library assesses fines for overdue book as follows. On the first day that a book is overdue, the total fine is $0.10, for each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount, what is the total fine for a book on the fourth day it is overdue.

$0.60
$0.70
$0.80
$0.90
$1.00

OA:B

i know, this seems simple, but couldnt crack it,,,,,,,,,,,,,i dont know what my brain is thinking,,,,may be a movie or a budlight,,,,,,,


Day 1 : 0.1
Day 2 : Min{0.1x2,0.1+0.3}=0.2
Day 3 : Min{0.2x2,0.2+0.3}=0.4
Day 4 : Min{0.4x2,0.4+0.3}=0.7

And thus B
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A certain library assesses fines for overdue books as follow [#permalink]

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A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is increased by $0.30 or doubled, whichever results in a lesser amount. What is the total for a book on the fourth day it is overdue?

A. $0.60
B. $0.70
C. $0.80
D. $0.90
E. $1.00

i approached it and got 1.00, but i cant understand why .70, which is B
Someone care to show me how to approach this question
thanks
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manalq8 wrote:
A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is increased by $0.30 or doubled, whichever results in a lesser amount. What is the total for a book on the fourth day it is overdue?

A. $0.60
B. $0.70
C. $0.80
D. $0.90
E. $1.00

i approached it and got 1.00, but i cant understand why .70, which is B
Someone care to show me how to approach this question
thanks


Notice that, fines are already cumulative: "For each additional day that the book is overdue, the total fine is ..."

1st day fine - 0.1
2nd day fine - 0.1*2=0.2 (as doubling gives lower value)
3rd day fine - 0.2*2=0.4 (as doubling gives lower value)
4th day fine - 0.4+0.3=0.7 (as doubling gives higher value we add 0.3 this time)

Answer: B.
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Re: A certain library assesses fines for overdue books as follow [#permalink]

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the total fine is increased by $0.30 or doubled, whichever results in a lesser amount - Keep the bolded phrases in mind .. it is quite confusing though ..
Day 1 - $.10
Day 2- $.10 *2 or $.10+$.30 (Whichever results in a lesser amount), hence its $.20
Day 3 - $.20*2 or $.20+$.30, $.40 as its lesser
Day 4 - $.40*2 or $.40+$.30, $.70 as this is lesser

So, Ans B.

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Re: A certain library assesses fines for overdue books as follow [#permalink]

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New post 20 Apr 2013, 05:08
cyberjadugar wrote:
Hi,

I am little confused, since the question mentions that the total fine be increased by 0.3 or double, won't the question be solved in following way:

day 1 - 0.1
day 2 - 2*0.1 = 0.2
day 3 (total due = 0.3, day 1 + day 2) = 0.6
day 4 = 0.9

can anyone please point out the mistake in my understanding of the question?

Regards,


Total fine at the end of the 2nd day = 0.2. This means that the total fine, including the past fines, at the end of the second day is 0.2. Notice that 0.1 has already been accounted for.Thus, when you are calculating the total fine at the end of the third day, you refer to 0.2. Thus, total fine at the end of the third day is 0.2*2=0.4.
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Re: Total fine of book on the 4th day of its overdue ? [#permalink]

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New post 23 Apr 2013, 03:17
This one's tricky for sure.
Easy to fall for D.
Here's the solution
Day 1 = 0.1$
Day 2 ( Double or increase by 0.3$, chose the minimum one)
Option1: Double -> 0.1*2= 0.2$
Option2: Increase by 0.3$ -> 0.1+0.3 = 0.4$
Minimum one: 0.2$
Day 3
Option1: Double -> 0.2*2=0.4$
Option2: Increase by 0.3$ -> 0.2+0.3=0.5$
Minimum one: 0.4$
Day 4
Option1: Double -> 0.4*2=0.8$
Option2: Increase by 0.3$ -> 0.4+0.3=0.7$
Minimum one: 0.7$
hence the OA.
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Re: A certain library assesses fines for overdue books as follow [#permalink]

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New post 05 Sep 2013, 11:01
Bunuel,

I am finding it tough solving 700+ questions, getting 70% accuracy, and thats quality in questions. Working on improvement.

But these 600-700 questions looks very school like stuff. Are they really 600 level questions ? or 600 level is quite low?

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New post 05 Sep 2013, 11:21
ygdrasil24 wrote:
Bunuel,

I am finding it tough solving 700+ questions, getting 70% accuracy, and thats quality in questions. Working on improvement.

But these 600-700 questions looks very school like stuff. Are they really 600 level questions ? or 600 level is quite low?


44% of the users answered this question incorrectly, so this question is not that easy. 600+ is about right for it.
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A certain library assesses fines for overdue books as follow [#permalink]

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For the ease of calculation, I removed the decimal point from the question as well as from the OA's

1st day = 10

2nd day = 10*2 = 20 {10+30>10*2}

3rd day = 20*2 = 40 {20+30>20*2}

4th day = 40+30 = 70 {40+30 < 40*2}

Answer = B
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hey bunuel
I followed the wrong strategy earlier.
Do u have more questions like this to practice..
Thanx.

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Re: A certain library assesses fines for overdue books as follow [#permalink]

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hey bunuel
I followed the wrong strategy earlier.
Do u have more questions like this to practice..
Thanx.


Similar questions to practice:
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Re: A certain library assesses fines for overdue books as follow [#permalink]

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Hi ALL,

This question includes a 'conditional statement' that effects how you're supposed to handle each "step" in the math:

"for each additional day....., the total fine is EITHER increased by 30 cents OR doubled, whichever results in the LESSER AMOUNT."

Since we're asked to calculate a book that is 4 days overdue, we just have to consider each possible outcome on each day, then choose the one that leads to the "lesser amount"

Day 1: 10 cents

Day 2: 10 + 30 = 40 cents; 10(2) = 20 cents
20 cents is LOWER, so the fine is NOW 20 cents

Day 3: 20 + 30 = 50 cents; 20(2) = 40 cents
40 cents is LOWER, so the fine is NOW 40 cents

Day 4: 40 + 30 = 70 cents; 40(2) = 80 cents
70 cents is LOWER, so the final fine is 70 cents.

Final Answer:
[Reveal] Spoiler:
B


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A certain library assesses fines for overdue books as follows. O [#permalink]

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New post 30 Apr 2015, 06:03
This question is really sneaky, like most people I answered 0.8, however, the method required here is not calculating both methods over the total time period, but repeating the process for each day separately for each day, and choosing the one which yields the least costs for everyday seperately based on the fine of the previous day. However, i think this question is flawed. I would say both methods are perfectly reasonable to use based on the text, since it does not specifically state that these rates are calculated separately for each day or for the entire period.

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GMAT 1: 600 Q48 V27
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Re: A certain library assesses fines for overdue books as follow [#permalink]

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New post 30 Dec 2015, 14:08
Is this 600-level? What a complicated way to calculate fine though...

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Re: A certain library assesses fines for overdue books as follow   [#permalink] 30 Dec 2015, 14:08

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