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# A certain list consists of 21 different numbers. If n is in

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Intern
Joined: 25 Sep 2004
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A certain list consists of 21 different numbers. If n is in [#permalink]

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03 Oct 2004, 07:27
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A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?

A. 1/20

B. 1/6

C. 1/5

D. 4/21

E. 5/21

Kudos [?]: 146 [0], given: 0

Joined: 31 Dec 1969

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Location: Russian Federation
GMAT 3: 740 Q40 V50
GMAT 4: 700 Q48 V38
GMAT 5: 710 Q45 V41
GMAT 6: 680 Q47 V36
GMAT 9: 740 Q49 V42
GMAT 11: 500 Q47 V33
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WE: Supply Chain Management (Energy and Utilities)

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03 Oct 2004, 07:41
C. 1/5

n=(4)*(K/20), where (K/20) = AM of the 20 numbers.
=> n= 1/5.

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Director
Joined: 16 Jun 2004
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03 Oct 2004, 08:16
B. 1/6.

1.X+n = 21Y

2. also, n=4X/20 = (1/5)X

substituting 2 in 1 => X+X/5 = 21Y =>n=(21/6)Y

we need to find n/21Y =?

=>(21/6)Y/21Y = 1/6

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Manager
Joined: 26 Sep 2004
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03 Oct 2004, 09:36
Either yu r posting questions or yu r the first one to answer them venkune .
_________________

Franky
http://franky4gmat.blogspot.com

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Manager
Joined: 21 Aug 2004
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08 Oct 2004, 10:26
A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?

A. 1/20

B. 1/6

C. 1/5

D. 4/21

E. 5/21

Let X be the sum of the other 20, then it means that n= 4X/20 = X/5
Total of 21 numbers then become X + X/5 = 6x/5

Fraction of n = X/5 divided by 6x/5 = 1/6

Kudos [?]: 36 [0], given: 0

Re: PS: A.M   [#permalink] 08 Oct 2004, 10:26
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