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from statement 1, the list can be -2, -5, -10. or 2, 5, 10. (but the smallest and the biggest must be positive, so -2, 4, 5, 10 wouldn't work with this)

from statement 2, the list has to be even. -2, 1, 3, 5 or -2, -4, -5, -10 or 1, 2, 4, 5

Ah, right. I kept getting hung up on the fact that we do not know if 0 is in the list or not, but from stat 1, we should be able to conclude that 0 isnt in the list because the only options are all negative integers, or all positive.

Re: Stuck with an easy number property....:( [#permalink]

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09 Jun 2009, 10:37

I think, the answer should be Neither 'A' nor 'B', nor 'A + B', Because 0 can also be a part of the list, then the product would come out to be 0 which is neither a positive nor a negative integer.
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a set can be (2,3,4) or (-4,-3,-2) product is positive and negative in these cases. Not sufficient.

b set can be (0,2) or (-2,0,1,2) where product is neither positive nor negative. And for set (1,2) its positive.Not sufficient.

a+b gives (1,2,4,5) its positive.

(-1,-2) is positive too. Also the set can't have 0 as its element as product of highest and lowest digits is positive meaning - (-2,-1,0,2) is not possible.

Hence C.
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