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# A certain rectangular window is twice as long as it is wide.

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A certain rectangular window is twice as long as it is wide. [#permalink]

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17 Dec 2012, 06:21
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A certain rectangular window is twice as long as it is wide. If its perimeter is 10 feet, then its dimensions in feet are

(A) 3/2 by 7/2
(B) 5/3 by 10/3
(C) 2 by 4
(D) 3 by 6
(E) 10/3 by 20/3
[Reveal] Spoiler: OA

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Re: A certain rectangular window is twice as long as it is wide. [#permalink]

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17 Dec 2012, 06:26
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A certain rectangular window is twice as long as it is wide. If its perimeter is 10 feet, then its dimensions in feet are

(A) 3/2 by 7/2
(B) 5/3 by 10/3
(C) 2 by 4
(D) 3 by 6
(E) 10/3 by 20/3

Given that P = 2l + 2w = 10, where l and w are the length and width in feet, respectively. Since, also given that l = 2w, then we have that 2l + l = 10 --> l = 10/3 --> w = l/2 = 10/6 = 5/3.

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Re: A certain rectangular window is twice as long as it is wide. [#permalink]

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17 Dec 2012, 06:31
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A certain rectangular window is twice as long as it is wide. If its perimeter is 10 feet, then its dimensions in feet are

(A) 3/2 by 7/2
(B) 5/3 by 10/3
(C) 2 by 4
(D) 3 by 6
(E) 10/3 by 20/3

L = 2W

Perimeter = 2(L+W) = 2(2W + W) = 6W = 10(given)
W = 10/6 = 5/3
L = 2W = 10/3

Answer will be B
Hope it helps!
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Re: A certain rectangular window is twice as long as it is wide [#permalink]

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25 Dec 2012, 13:01
megafan wrote:
A certain rectangular window is twice as long as it is wide. If its perimeter is 10 feet, then its dimensions in feet are

(A) $$\frac{3}{2}$$ by $$\frac{7}{2}$$

(B) $$\frac{5}{3}$$ by $$\frac{10}{3}$$

(C) $$2$$ by $$4$$

(D) $$3$$ by $$6$$

(E) $$\frac{10}{3}$$ by $$\frac{20}{3}$$

Relatively easy question, except for the confusing term - "twice as long as it is wide", which I happen to screw up over. Did someone happen to compile a list of these confusing statements in word problems? If so, please do share, it would be immensely helpful for me, and I am sure for other members as well.

Ya its quite easy....

twice as long as it is wide means : l=2w

Given p=10
2(l+w)=10
l+w=5
2w+w=5
w=5/3
and l = 10/3

If u feel difficult in understanding "twice as long as it is wide", since length should be always greater than width and here it is twice l=2w
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A certain rectangular window is twice as long as it is wide. If [#permalink]

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04 Apr 2013, 15:09
bmwhype2 wrote:
A certain rectangular window is twice as long as it is wide. If its perimeter is 10 feet, then its dimensions in feet are
(A) 3/2 by 7/2
(B) 5/3 by 10/3
(C) 2 by 4
(D) 3 by 6
(E) 10/3 by 20/3

my answer was B. Answer Key says E.

Width $$=$$ $$x$$
Length$$=$$ $$2x$$
Perimeter $$= x+x+2x+2x = 6X$$
$$6x = 10$$
$$x= \frac{5}{3}$$

Therefore, dimensions are:
Width $$= \frac{5}{3}$$
Length $$= 2*\frac{5}{3} = \frac{10}{3}$$

B all the way

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Re: A certain rectangular window is twice as long as it is wide. [#permalink]

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30 May 2014, 11:04
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Re: A certain rectangular window is twice as long as it is wide. [#permalink]

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31 May 2014, 21:59
A certain rectangular window is twice as long as it is wide. If its perimeter is 10 feet, then its dimensions in feet are

(A) 3/2 by 7/2
(B) 5/3 by 10/3
(C) 2 by 4
(D) 3 by 6
(E) 10/3 by 20/3

We can eliminate C,D,E as not giving 10 feeet as perimeter. In choice A, 3/2=1.5 and 7/2=3.5 so it is not double difference. The answer is B

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A certain rectangular window is twice as long as it is wide. If [#permalink]

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19 Jan 2015, 02:02
The dimesnsions of the box are:
w = w
l = 2w

Perimeter:
2w + 2(2w) = 10
2w + 4w = 10
6w = 10
w = 10 / 6
w = 5 / 3

l = 2w
l = 2 (5/3)
l = 10 / 3

So. the dimensions are 5/3 and 10/3, ANS B

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Re: A certain rectangular window is twice as long as it is wide. [#permalink]

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19 Jan 2015, 12:48
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Expert's post
HI All,

Many Test Takers would approach this with a combination of algebra and geometry rules, which is fine - the math is easy enough to do. On Test Day though, you have 2 goals when dealing with a question:

1) Get it correct, if possible.
2) Answer it in the fastest way possible.

Since the answer choices ARE numbers, and the prompt describes some rather specific facts, you can use the answers to your advantage and TEST THE ANSWERS.

We're told 2 things about a rectangle:
1) It's length is TWICE it's width.
2) It's perimeter is 10

We're asked for the dimensions of the rectangle.

Looking at the answer choices, there are some really easy answers to knock out....

Answer C: 2 by 4......this perimeter would = 12, not 10. ELIMINATE C.
Answer D: 3 by 6......this perimeter would = 18, not 10. ELIMINATE D.
Answer E: 10/3 by 20/3......this perimeter would be > 18, not 10. ELIMINATE E.

With the remaining 2 answers, only 1 of them has a length that is TWICE the width....

Answer A: 3/2 and 7/2.....7/2 is NOT TWICE 3/2. Eliminate A.

[Reveal] Spoiler:
B

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Re: A certain rectangular window is twice as long as it is wide. [#permalink]

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27 Feb 2016, 02:36
Hello from the GMAT Club BumpBot!

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Re: A certain rectangular window is twice as long as it is wide. [#permalink]

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21 Jun 2016, 09:23
A certain rectangular window is twice as long as it is wide. If its perimeter is 10 feet, then its dimensions in feet are

(A) 3/2 by 7/2
(B) 5/3 by 10/3
(C) 2 by 4
(D) 3 by 6
(E) 10/3 by 20/3

We set up the dimensions of the rectangular window as w = width and l = length.

We are given that the rectangular window is twice as long as it is wide. Thus we can say:

l = 2w

We also know that the perimeter is 10 feet, so we can say:

2l + 2w = 10

We can now substitute in 2w for l and we have:

2 x 2w + 2w = 10

4w + 2w = 10

6w = 10

w = 10/6 = 5/3

Because we know that the length is twice the width, we know that the length is:

2 x 5/3 = 10/3

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Re: A certain rectangular window is twice as long as it is wide. [#permalink]

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05 Jul 2017, 20:16
Take width as x, length is 2x. Perimeter = x+2x+x+2x = 6x = 10; x=5/3

Hence length is 10/3 and width is 5/3
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Re: A certain rectangular window is twice as long as it is wide.   [#permalink] 05 Jul 2017, 20:16
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