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Posts: 1231
A certain right triangle has sides of length x, y, and z, where x < y
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06 Dec 2020, 11:59
Top Contributor
tonebeeze wrote:
A certain right triangle has sides of length x, y, and z, where x < y < z. If the area of this triangular region is 1, which of the following indicates all of the possible values of y?
A. \(y > \sqrt {2}\)
B. \(\frac {\sqrt {3}} {2} < y < \sqrt {2}\)
C. \(\frac {\sqrt {2}} {3} < y < \frac {\sqrt {3}} {2}\)
D. \(\frac {\sqrt {3}} {4} < y < \frac {\sqrt {2}} {3}\)
E. \(y < \frac {\sqrt {3}}{4}\)
\(x, \ y, \, and \ z \ are \ the \ sides \ of \ a \ right \ triangle \ where \ x<y<z \ so \ z \ must \ be \ the \ hypotenuse.\)
Re: A certain right triangle has sides of length x, y, and z, where x < y
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02 Dec 2021, 14:04
So I was stuck on this for a bit but then it hit me.
We know x * y = 4
And x < y
Options B C D E all give y constraints that are less than 2 AND if Y is less then two we will never be able to find an X value LESS than y that will allow us to multiply to a product of 4.
Therefore,
The only possible constraint would be y > radical2
Posted from my mobile device
gmatclubot
Re: A certain right triangle has sides of length x, y, and z, where x < y [#permalink]
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