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# A certain roller coaster has 3 cars and a passenger is

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A certain roller coaster has 3 cars and a passenger is [#permalink]

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23 Dec 2004, 09:55
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A certain roller coaster has 3 cars and a passenger is likely to rde in any one of the 3 cars each time the passenger rides the roller coaster. If a certain passenger is to ride the coaster 3 times, what is the probability that the passenger will ride in each of the 2 cars.

A. 0
B. 2/9
C. 1/9
D. 1
E. 1/3

What is the correct answer and why? I have the answer, don;t know why.
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23 Dec 2004, 11:52
I do not get this piece:
what is the probability that the passenger will ride in each of the 2 cars.
+++++
Does it mean that in 3 attempts the passenger will be riding the same car twice?If that is the case,what is the purpose of "each"?Tx.

Anna

pb_india wrote:
A certain roller coaster has 3 cars and a passenger is likely to rde in any one of the 3 cars each time the passenger rides the roller coaster. If a certain passenger is to ride the coaster 3 times, what is the probability that the passenger will ride in each of the 2 cars.

A. 0
B. 2/9
C. 1/9
D. 1
E. 1/3

What is the correct answer and why? I have the answer, don;t know why.

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We can crack the exam together

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23 Dec 2004, 16:09
B - will explain if correct
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23 Dec 2004, 16:10
Sorry correction E
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23 Dec 2004, 17:54
rahul you're not making any sense. Doesnt' the question actually ask what is the probability that the person will ride in each of the 3 cars? That's the only thing that makes sense.

If so, then I think the answer is as follows:

Total number of combinations of cars the person could ride in:
3x3x3 = 27

Total number of combinations we like:
1,2,3
1,3,2
2,1,3
2,3,1
3,1,2
3,2,1

= 6/27 = 2/9

Right?
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23 Dec 2004, 18:01
I think this question has a typo or else it is very ambiguous. As hilairity said, it should have been "3" cars at the end.
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Paul

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23 Dec 2004, 21:15
Guys,
Thanks a lot. It was a typo on my part. It is "3" cars and answer is correct:
2/9

Thanks again for the explanation.
23 Dec 2004, 21:15
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