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# A certain roller coaster has 3 cars, and a passenger is

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Manager
Joined: 30 Jan 2006
Posts: 62

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A certain roller coaster has 3 cars, and a passenger is [#permalink]

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07 Aug 2007, 12:09
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A certain roller coaster has 3 cars, and a passenger is equally likely to ride in any 1 of the
3 cars each time that passenger rides the roller coaster. If a certain passenger is to ride
the roller coaster 3 times, what is the probability that the passenger will ride in each of
the 3 cars?
A. 0
B. 1/9
C. 2/9
D. 1/3
E. 1

Kudos [?]: 20 [0], given: 0

Senior Manager
Joined: 24 Nov 2006
Posts: 349

Kudos [?]: 28 [0], given: 0

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07 Aug 2007, 12:59
smily_buddy wrote:
A certain roller coaster has 3 cars, and a passenger is equally likely to ride in any 1 of the
3 cars each time that passenger rides the roller coaster. If a certain passenger is to ride
the roller coaster 3 times, what is the probability that the passenger will ride in each of
the 3 cars?
A. 0
B. 1/9
C. 2/9
D. 1/3
E. 1

Probab to ride in any of the cars: 1/3.

Cars: A, B, C.

Number of possible rides: number of combinations of A, B, C where no letter (car) is repeated = 3! = 6.

Total number of possible rides = 3x3x3 = 27.

Probab = 6/27.

Kudos [?]: 28 [0], given: 0

VP
Joined: 10 Jun 2007
Posts: 1431

Kudos [?]: 388 [0], given: 0

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07 Aug 2007, 13:13
smily_buddy wrote:
A certain roller coaster has 3 cars, and a passenger is equally likely to ride in any 1 of the
3 cars each time that passenger rides the roller coaster. If a certain passenger is to ride
the roller coaster 3 times, what is the probability that the passenger will ride in each of
the 3 cars?
A. 0
B. 1/9
C. 2/9
D. 1/3
E. 1

C.
First pick is any
Second pick is 2/3
Third pick is 1/3
2/3 * 1/3 = 2/9.

Kudos [?]: 388 [0], given: 0

Manager
Joined: 30 Jan 2006
Posts: 62

Kudos [?]: 20 [0], given: 0

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07 Aug 2007, 15:19
Great the OA is C...

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GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5032

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Location: Singapore

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07 Aug 2007, 17:24
First time -> choice of any 3 cars
second time -> choice of any 2 cars
Third time -> choice of 1 car

Total number of ways for passenger to ride in each of 3 cars = 6
Total number of ways a passenger can ride (over 3 rounds) = 27

P = 6/27 = 2/9

Kudos [?]: 457 [0], given: 0

07 Aug 2007, 17:24
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