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Re: A certain store will order 25 crates of apples. The apples will be of [#permalink]
(x-1)+2x=25 –> x=9
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Re: A certain store will order 25 crates of apples. The apples will be of [#permalink]
There are 3 categories of apple.
We can divide 25 by 3, get 8 and remainder 1.
So we can get 9.
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Re: A certain store will order 25 crates of apples. The apples will be of [#permalink]
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Total crates: 25

=> 3 Varieties: McIntosh, Rome, and Winesap

=> Conditions: Winesap > McIntosh (crates) and Winesap > Rome (crates)

So, the number of crates of Mcintosh can be lesser than those of crates of Rome, or they both can be equal.

=> A rough division of 25 in 3 gives us 9, 8, 8

Winesap: 9; McIntosh: 8 and Rome: 8

Any other combinations will increase the crates of Winesap. For example McIntosh : 8 > Rome 7 will give Winesap = 10.

So, the minimum possible crates for Winseap = 9

Answer C
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Re: A certain store will order 25 crates of apples. The apples will be of [#permalink]
Wanted to see if my approach is correct:

W + M + R = 25

&, W > M & W>R is what we want!

So, adding the 2 inequalities,
2W > M + R

Now, from the first equation, we have M + R = 25 - W

Put this in the inequality,

2W > 25-W => 3W > 25 => W > 8.something.

Since create has to be an integer and has to be greater than 8, next smallest possible value is 9.

Hence, answer is (C)
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Re: A certain store will order 25 crates of apples. The apples will be of [#permalink]
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Bunuel wrote:
A certain store will order 25 crates of apples. The apples will be of three different varieties—McIntosh, Rome, and Winesap—and each crate will contain apples of only one variety. If the store is to order more crates of Winesap than crates of McIntosh and more crates of Winesap than crates of Rome, what is the least possible number of crates of Winesap that the store will order?


A. 7

B. 8

C. 9

D. 10

E. 11


If the 25 crates are equally divided then \(\frac{25}{3}=8^+\); Given that \(W>M, W>R\)

So, if W takes 9 then M and R take 8 each. This will least possible option for W under the given condition.

The answer is \(C\)
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Re: A certain store will order 25 crates of apples. The apples will be of [#permalink]
target find least value which is greater than the other two options of apples i.e Mcintosh & Rome
using answer options
if Winesap is 8 then other two are 7 each ; 25-14 ; 11 which is not valid
if winesapp is 9 then other two are max 8 each ; 25-16 ; 9 correct and matching to option
C is correct

Bunuel wrote:
A certain store will order 25 crates of apples. The apples will be of three different varieties—McIntosh, Rome, and Winesap—and each crate will contain apples of only one variety. If the store is to order more crates of Winesap than crates of McIntosh and more crates of Winesap than crates of Rome, what is the least possible number of crates of Winesap that the store will order?


A. 7

B. 8

C. 9

D. 10

E. 11


(PS01233)
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Re: A certain store will order 25 crates of apples. The apples will be of [#permalink]
Bunuel wrote:
A certain store will order 25 crates of apples. The apples will be of three different varieties—McIntosh, Rome, and Winesap—and each crate will contain apples of only one variety. If the store is to order more crates of Winesap than crates of McIntosh and more crates of Winesap than crates of Rome, what is the least possible number of crates of Winesap that the store will order?


A. 7

B. 8

C. 9

D. 10

E. 11

(PS01233)


Given:
M + R + W =25
M < W -------(1)
R < W -------(2)
Adding 1 & 2
M + R < 2W
Adding W both sides
M + R + W < 3W

=> 25 < 3W

W > 25/3
W > 8.33

W = 9
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Re: A certain store will order 25 crates of apples. The apples will be of [#permalink]
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