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26 Sep 2012, 11:34
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82% (00:45) correct 18% (01:04) wrong based on 969 sessions

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A club collected exactly $599 from its members. If each member contributed at least$12, what is the greatest number of members the club could have?

(A) 43
(B) 44
(C) 49
(D) 50
(E) 51
[Reveal] Spoiler: OA

Last edited by Bunuel on 26 Sep 2012, 12:08, edited 1 time in total.
Renamed the topic.

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Re: A club collected exactly $599 from its members. If each [#permalink] ### Show Tags 26 Sep 2012, 12:17 3 This post received KUDOS Expert's post 2 This post was BOOKMARKED Archit143 wrote: A club collected exactly$599 from its members. If each member contributed at least $12, what is the greatest number of members the club could have? (A) 43 (B) 44 (C) 49 (D) 50 (E) 51 Obviously club could not have 50 or more members, since$12*50=$600>$599. What about 49? If 48 members contributes $12 ($12*48=$576) and 1 member contributed the remaining$23, then the club would have is 48+1=49.

OR: $$12x\leq{599}$$ --> $$x\leq{49\frac{11}{12}}$$ --> $$x=49$$ (since x must be an integer).

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02 Jul 2014, 02:47
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Rounded off 599 to 600 (Its divisible of 12)

$$\frac{600}{12} = 50$$

Members should be atleast 1 less that 50

50-1 = 49

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21 Jun 2016, 10:34
1
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Expert's post
Archit143 wrote:
A club collected exactly $599 from its members. If each member contributed at least$12, what is the greatest number of members the club could have?

(A) 43
(B) 44
(C) 49
(D) 50
(E) 51

Let's first divide= 599 by 12 (the minimum amount each member could contribute) and then use the remainder to finish the problem.

599/12 = 49 R 11

This means that: 49 people x $12 + 1 person x$11 = $599 We see that if 49 members each contribute$12, someone would have to contribute the extra $11. Note that, since each member contributed at least$12, the $11 could not have come from an additional member. Therefore, the extra$11 must have been contributed by one (or more) of the existing 49 members. Regardless of who contributed the extra $11, the maximum number of members the club could have is 49. Answer is C. _________________ Jeffery Miller Head of GMAT Instruction GMAT Quant Self-Study Course 500+ lessons 3000+ practice problems 800+ HD solutions Kudos [?]: 768 [1], given: 5 GMAT Club Legend Joined: 09 Sep 2013 Posts: 17669 Kudos [?]: 272 [0], given: 0 Re: A club collected exactly$599 from its members. If each [#permalink]

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18 Jul 2017, 11:05
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