shreyashid wrote:

Sorry, I am convinced about the first explanation regarding dividing the groups into 3 men*3 women+2 men* 4 women.

However, when confronted with the problem , I calculated it in the other way as stated by many above . The discussion on this other approach has left me confused, Can anyone help me with this to clarify my concepts please ?

So I calculated the number of ways groups can be formed as:

8C2 * 5C3 * 8C1

(men) (women) (remaining bunch as after removing 5 people we have 8 m+w remaining)

**I am assuming it is correct till here. Please correct me if otherwise**

Now I am having trouble in removing the overlap .

I did it as 2C2* 5C3 * 8C2 which is giving a wrong answer.

Thanks

Hi,

8C2 * 5C3 * 8C1 as a solution for this Q is wrong...

this would be a valid solution if the Q said that you have to choose

"A committee of 6 is chosen from 8 men and 5 women so as to contain 2 men and 3 women and one child from a group of 8 childrens"...

the solution

8C2 * 5C3 * 8C1 treats the 8C1 as an independent group..

but you have these 8 people as a part of the other two groups..

so what happens/.. it gives us duplicate scenarios..

I'lljust point to one..

say there are 3 men A,B,C in the group...

A and B are choosen in 8C2 and C is choosen in 8C1..

in another scenario A and C are choosen in 8C2 and B is choosen in 8C1..

so you see both are same case and that is why

8C2 * 5C3 * 8C1 is wrong...

Hope it helps

_________________

Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372

Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html