A computer chip manufacturer expects the ratio of the number of defect : GMAT Problem Solving (PS)
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# A computer chip manufacturer expects the ratio of the number of defect

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A computer chip manufacturer expects the ratio of the number of defect [#permalink]

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26 Feb 2009, 21:30
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67% (02:29) correct 33% (01:50) wrong based on 72 sessions

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Shipment ------No. of Defective Chips/shipment---Total Chips in shipment
S1 -------------- 2 -----------------------------------------------5000
S2 -------------- 5 ------------------------ ----------------------12000
S3 -------------- 6 ----------------------------------------------- 18000
S4 -------------- 4 ----------------------------------------------- 16000

A computer chip manufacturer expects the ratio of the number of defective chips to be total number of chips in all future shipments equal to the corresponding ratio for shipments S1,S2,S3 and S4 combined as shown in the table above. What is the expected number of defective chips in a shipment of 60000 chips?

A. 14
B. 20
C. 22
D. 24
E. 25

OPEN DISCUSSION OF THIS QUESTION IS HERE: a-computer-chip-manufacturer-expects-the-ratio-of-the-number-126050.html
[Reveal] Spoiler: OA

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Last edited by Bunuel on 22 Mar 2015, 04:47, edited 2 times in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
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Re: A computer chip manufacturer expects the ratio of the number of defect [#permalink]

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26 Feb 2009, 22:33
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keeshafey wrote:
I'm not understanding the question....what does it mean "the shipments combined?"

It means on future shipment ( Defective chips)/ ( Total no of chips) = S1=S2=S3=S4.

so x/60,000 = 2/5000 = 5/12000 = 6/18,000= 4/16,000.

Solve for X and you will get x=20.

Hope so you got it.
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Re: A computer chip manufacturer expects the ratio of the number of defect [#permalink]

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26 Feb 2009, 22:34
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Hi keeshafey,

What it's trying to say is that in future shipments,

(The number of defective chips) / (Total chips) = {Defective chips (S1 + S2 + S3+ S4)} / {Total Chips (S1 + S2 + S3+ S4)}

R.H.S = (2+5+6+4)/(5000 + 12000 + 18000 + 16000)
= 17/51000

On L.H.S side, you are given that (Total chips) = 60000

Therefore, (The number of defective chips) = 20

Regards,
Technext
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Re: A computer chip manufacturer expects the ratio of the number of defect [#permalink]

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22 Mar 2015, 00:41
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Re: A computer chip manufacturer expects the ratio of the number of defect [#permalink]

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22 Mar 2015, 04:46
Shipment ------No. of Defective Chips/shipment---Total Chips in shipment
S1 -------------- 2 -----------------------------------------------5000
S2 -------------- 5 ------------------------ ----------------------12000
S3 -------------- 6 ----------------------------------------------- 18000
S4 -------------- 4 ----------------------------------------------- 16000

A computer chip manufacturer expects the ratio of the number of defective chips to be total number of chips in all future shipments equal to the corresponding ratio for shipmemts S1,S2,S3 and S4 comined as shown in the table above. What is the expected number of defective chips in a shipment of 60000 chips?

A. 14
B. 20
C. 22
D. 24
E. 25

Set up equation: $$\frac{x}{60,000}=\frac{2+5+6+4}{5,000+12,000+18,000+16,000}$$ --> $$x=20$$;

Or: $$2+5+6+4=17$$ defective chips in $$5,000+12,000+18,000+16,000=51,000$$ chips, so $$\frac{17}{51,000}=\frac{1}{3,000}$$: 1 in 3,000. So, expected number of defective chips in a shipment of 60,000 chips is $$\frac{60,000}{3,000}=20$$.

OPEN DISCUSSION OF THIS QUESTION IS HERE: a-computer-chip-manufacturer-expects-the-ratio-of-the-number-126050.html
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Re: A computer chip manufacturer expects the ratio of the number of defect   [#permalink] 22 Mar 2015, 04:46
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