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A computer routine was developed to generate two numbers, ( x,y), the

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HKD1710
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A computer routine was developed to generate two numbers, ( x,y), the [#permalink] New post   15 Nov 2018, 10:36
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A computer routine was developed to generate two numbers, ( x,y), the first being a random number between 0 and 100 inclusive, and the second being less than or equal to the square root of the first. Each of the following pairs satisfies this routine EXCEPT:

(A) (99, 10)
(B) (85, 9)
(C) (50, 7)
(D) (1 , 1)
(E) (1, 0)

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A
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A computer routine was developed to generate two numbers, ( x,y), the [#permalink] New post   15 Nov 2018, 14:25
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amhill4 wrote:
99 is slightly less than 100, which has a square root of 10. Square root of 99 is therefore less than 10, so answer is B


Hey amhill4, did you mean to write A instead of B?
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Re: A computer routine was developed to generate two numbers, ( x,y), the [#permalink] New post   15 Nov 2018, 10:46
10^2 = 100 which is more than 99, hence the pair (99,10) does not satisfy the given condition.

Option A
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Re: A computer routine was developed to generate two numbers, ( x,y), the [#permalink] New post   15 Nov 2018, 11:40
HKD1710 wrote:
A computer routine was developed to generate two numbers, ( x,y), the first being a random number between 0 and 100 inclusive, and the second being less than or equal to the square root of the first. Each of the following pairs satisfies this routine EXCEPT:

(A) (99, 10)
(B) (85, 9)
(C) (50, 7)
(D) (1 , 1)
(E) (1, 0)

Project PS Butler : Question #20


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the quant became like walking on clouds :lol: HKD1710 your quant posts boosted my confidence in quant :grin:

\(10^2 = 100\)

so option A is doesnt satidfy conditon
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Re: A computer routine was developed to generate two numbers, ( x,y), the [#permalink] New post   15 Nov 2018, 14:17
99 is slightly less than 100, which has a square root of 10. Square root of 99 is therefore less than 10, so answer is B
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Re: A computer routine was developed to generate two numbers, ( x,y), the [#permalink] New post   15 Nov 2018, 14:28
Whoops, yeah I meant to write A I swear! :roll:
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Re: A computer routine was developed to generate two numbers, ( x,y), the [#permalink] New post   27 Nov 2018, 13:08
A computer routine was developed to generate two numbers, ( x,y), the first being a random number between 0 and 100 inclusive, and the second being less than or equal to the square root of the first. Each of the following pairs satisfies this routine EXCEPT:

(A) (99, 10)
(B) (85, 9)
(C) (50, 7)
(D) (1 , 1)
(E) (1, 0)

Sol-
A doesnt satisfy one of the conditions mentioned
10^2 is not 100.
Ans- (A)
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Re: A computer routine was developed to generate two numbers, ( x,y), the [#permalink] New post   03 Feb 2019, 23:01
I need help as when i read the question , the second should be less than or equal to square of first.

so if its (X,Y) then y<=X2???
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Re: A computer routine was developed to generate two numbers, ( x,y), the [#permalink] New post   04 Feb 2019, 10:56
Ana4001 wrote:
I need help as when i read the question , the second should be less than or equal to square of first.

so if its (X,Y) then y<=X2???


Hi Ana4001

It is "second being less than or equal to the square root of the first", i suppose you missed out on the bold part

it means y <= \(\sqrt{x}\)
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Re: A computer routine was developed to generate two numbers, ( x,y), the [#permalink] New post   02 Jul 2019, 18:55
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HKD1710 wrote:
A computer routine was developed to generate two numbers, ( x,y), the first being a random number between 0 and 100 inclusive, and the second being less than or equal to the square root of the first. Each of the following pairs satisfies this routine EXCEPT:

(A) (99, 10)
(B) (85, 9)
(C) (50, 7)
(D) (1 , 1)
(E) (1, 0)


Looking at the answer choices, we see that since √100 = 10, square root of 99 is less than 10, so (99,10) cannot be the pair of numbers chosen.

Answer: A
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Re: A computer routine was developed to generate two numbers, ( x,y), the [#permalink] New post   02 Sep 2021, 21:25
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Check by squaring the second numbers of the options

A. 10^2 = 100 (so this is where we can say for certain that the second number is not less than or equal to the square root of the first (99))

B.(85,9)- 9^2 = 81. Eliminate. So square root of 85 is > 9 or second number 9 is less than first number 85.

C.(50,7)- 7^2 = 49. Eliminate

D.(1,1) - 1^2 =1 .Eliminate

E. (1,0) - 1^2 =1 which is >0 and hence eliminate.

(option a)

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A computer routine was developed to generate two numbers, ( x,y), the [#permalink] New post   18 Feb 2022, 08:54
HKD1710 wrote:
A computer routine was developed to generate two numbers, ( x,y), the first being a random number between 0 and 100 inclusive, and the second being less than or equal to the square root of the first. Each of the following pairs satisfies this routine EXCEPT:

(A) (99, 10)
(B) (85, 9)
(C) (50, 7)
(D) (1 , 1)
(E) (1, 0)

Project PS Butler : Question #20


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Since 10 > \(\sqrt{99}\), statement A is a violation of the given rule.
We can check all other options satisfy the given rule.
Hence, A.
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A computer routine was developed to generate two numbers, ( x,y), the [#permalink]
18 Feb 2022, 08:54
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