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# A cop clocks a motorcyclist speeding down the highway at 90 mph. 2 mi

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Q48  V36 GMAT 2: 730  Q50  V38
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Re: A cop clocks a motorcyclist speeding down the highway at 90 mph. 2 mi [#permalink]
1
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Another way is just multiply both the speeds with all the options available, whichever gives you the distance traveled by the cop and the car as same is your answer.

But in this case solving the problem will take a lesser time, unless 6 was option A or B
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Re: A cop clocks a motorcyclist speeding down the highway at 90 mph. 2 mi [#permalink]
bike 90 mph = 1.5 miles/ minute
cop 120 mph = 2 miles/ minute

they both go the same distance (d) and bike gets 2 minute head start (t+2) and we'll call cop's time (t)
bike's equation: 1.5(t+2)=d this is R*T=D
cop's equation: 2t=d

we can set their d's equal since that's the point where they meet and we're trying to solve for t

1.5(t+2)=2t
t=6

I know other people explained it. I just wanted to boost my GMAT confidence and give it my own shot.
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Re: A cop clocks a motorcyclist speeding down the highway at 90 mph. 2 mi [#permalink]
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Re: A cop clocks a motorcyclist speeding down the highway at 90 mph. 2 mi [#permalink]
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