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# A cuboid pool, when it is half full, the water level height

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A cuboid pool, when it is half full, the water level height [#permalink]

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14 Apr 2006, 18:49
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A cuboid pool, when it is half full, the water level height is (Let it be H). If drain out 500 liters of water, the level is (Let it be h). What is volume of the pool?
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14 Apr 2006, 19:08
Is it 250*H/(H-h)?
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14 Apr 2006, 19:31
1000H/(H-h)

- Vipin
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14 Apr 2006, 20:09
Got that one wrong... Vipin is right.

If A is cross-sectional area, and V is volume:

AH=1/2*V (had this eqn the other way round in my calcs )
HA-hA=500

Thanks Vipin...
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15 Apr 2006, 01:49
vipin7um wrote:
1000H/(H-h)

- Vipin

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15 Apr 2006, 02:06
Volume of the pool = lb(2H) (assume l is length and b is breadth)

After draining:

500 = lb(H-h)

or lb = 500/(H-h)

substituting lb in the first eq

Volume = 1000H/(H-h)
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15 Apr 2006, 08:52
M8 wrote:
vipin7um wrote:
1000H/(H-h)

- Vipin

Hi M8,
Let us say the area is A.

=> V = A * 2H - (1)

Also 500 ltr of water reduces the hight from H to h

=> 500 = A * (H-h) - (2)

Solving (1) and (2) for A gives the Volume.

HTH...
15 Apr 2006, 08:52
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# A cuboid pool, when it is half full, the water level height

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