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1
2 00:00

Difficulty:   25% (medium)

Question Stats: 84% (02:21) correct 16% (03:01) wrong based on 55 sessions

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A customer buys two products, X and Y, and spends a total of $350. Both products come with rebate coupons. The rebate on the price of product X is 15 percent, and the rebate on the price of product Y is 10 percent. If x and y are the prices of products X and Y, respectively, before the rebate and the total rebate earned by the customer was$45, how much did each product cost?
A) x = $200, y =$150
B)x= $130, y =$220
C) x= $140, y =$210
D x = $300, y =$50
E)x = $175, y =$175

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Director  G
Joined: 19 Oct 2013
Posts: 504
Location: Kuwait
GPA: 3.2
WE: Engineering (Real Estate)

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Salsanousi wrote:
Abhi077 wrote:
A customer buys two products, X and Y, and spends a total of $350. Both products come with rebate coupons. The rebate on the price of product X is 15 percent, and the rebate on the price of product Y is 10 percent. If x and y are the prices of products X and Y, respectively, before the rebate and the total rebate earned by the customer was$45, how much did each product cost?
A) x = $200, y =$150
B)x= $130, y =$220
C) x= $140, y =$210
D x = $300, y =$50
E)x = $175, y =$175

x*(15/100) + y (10/100) = 45

15x + 10y = 4,500 (1)

x + y = 350
10x + 10y = 3,500 (2)

(1) - (2)
5x = 1,000
x = 200

Only answer A has x as 200.

You can do it as back solving also

200*(15/100) = 30
150*(10/100) = 15

30 + 15 = 45

Posted from my mobile device

Hi Salsanousi,

if x and y are the prices of the two products before the rebate , then shouldn't x + y = 395 ?
because total rebate is 45 and after the rebate 350 was paid .

and .85x + .90y= 350 ( This should be the price after the rebate IMO)
_________________
- Stne
Intern  B
Joined: 04 Nov 2017
Posts: 10

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muus wrote:
I think this question is wrong, the value 350 in the question should have been 305

It should be like this instead.

0.85x + 0.9y = 305

and

0.15x + 0.9y = 45

solving the two equations will give us

x = 200 and y = 150

$$\frac{85}{100}x+ \frac{90}{100}y=350 (1)$$
$$\frac{15}{100}x+ \frac{10}{100}y=45 (2)$$

Further simplification of (1)
85x + 90y=35000 -> 17x + 18y=7000
Further simplification of (2)
15x+10y=4500-> 3x+2y=900

So final two equations are
17x + 18y=7000
3x+2y=900

On solving these I am getting x =110 and y=255

Please let me know if I am making any mistake anywhere.Thank you.
_________________
- Stne
Senior Manager  D
Joined: 15 Feb 2018
Posts: 453

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Abhi077 wrote:
A customer buys two products, X and Y, and spends a total of $350. Both products come with rebate coupons. The rebate on the price of product X is 15 percent, and the rebate on the price of product Y is 10 percent. If x and y are the prices of products X and Y, respectively, before the rebate and the total rebate earned by the customer was$45, how much did each product cost?
A) x = $200, y =$150
B)x= $130, y =$220
C) x= $140, y =$210
D x = $300, y =$50
E)x = $175, y =$175

Total rebate = 45
This means that=> 350 - x = 45
After rebate the value was 305

which value when used in the equation 0.85 x + 0.90 y = 305

If you are comfortable with multiplication under time pressure, only A satisfies the above equation.
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# A customer buys two products, X and Y, and spends a total of \$350  