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# A dairy man pays \$ 6.4 per litre of milk; he adds water and

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Director
Joined: 13 Nov 2003
Posts: 788

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Location: BULGARIA
A dairy man pays \$ 6.4 per litre of milk; he adds water and [#permalink]

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23 Mar 2004, 01:57
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A dairy man pays \$ 6.4 per litre of milk; he adds water and
sells the mixture at \$ 8 per litre, thereby making 37.5% profit. Find the
proportion of water to milk received by the customers.

1) 1 : 15
2) 1 : 10
3) 1 : 20
4) 1 : 12

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Senior Manager
Joined: 02 Mar 2004
Posts: 327

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Location: There

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23 Mar 2004, 02:24
\$0-------------------------------\$64/11-----------------------------\$6.4

(64/10)-(64/11) = 64/110 64/11 - 0 = 64/11

64/110 : 64/11 = 1:10

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Director
Joined: 13 Nov 2003
Posts: 788

Kudos [?]: 64 [0], given: 0

Location: BULGARIA

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23 Mar 2004, 12:19
halle, I bow before you. Perfect.

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SVP
Joined: 30 Oct 2003
Posts: 1788

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Location: NewJersey USA

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23 Mar 2004, 14:23
8*(m+w) = 1.375 * 6.4 * m
8w = m( 6.4 * (1.25 + 0.125) - 8 )
w/m = 0.8(1.25+0.125) - 1 = 0.1
so w:m = 1:10

I was trying not to solve quant problems for some time and concentrate on verbal. But kpadma dragged me into this. I think it is all about addiction. I wanr everyone about this addiction and suggest concentrating on certain known weak points.

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GMAT Club Legend
Joined: 15 Dec 2003
Posts: 4284

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23 Mar 2004, 14:54
Price you would have to sell at in order to get 37.5% profit: 1.375*6.4\$ = 8.8\$
In order for you to still keep a 37.5% profit while selling the diluted milk at 8\$, then the .8\$ difference must represent the water proportion. Then water to milk: .8\$ / 8\$ = 1 : 10
_________________

Best Regards,

Paul

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Director
Joined: 03 Jul 2003
Posts: 651

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23 Mar 2004, 15:37
anandnk wrote:

Well, What can I say. I'm an addict, now!

Here is another method!

Customer gets 1 liter for \$8
Vender pays (1-x)*\$6.4 for that adulterated 1 liter milk and makes
37.5% profit.

Where X = water in 1 liter adulterated milk

6.4(1-x) * 1.375 = 8

Solve for X, we get 1/11.
Pure milk in 1 liter adultrated milk is 10/11

W:M = 1/11 : 10/11 = 1:10

Well, time for another round

Kudos [?]: 106 [0], given: 0

23 Mar 2004, 15:37
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# A dairy man pays \$ 6.4 per litre of milk; he adds water and

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