vksunder wrote:

A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?

a. 3q/200

b. 3q/2

c. 150q

d. q/100+50

e. 150/q

Could one of you please explain what 'in terms of q' mean in the question? Also, could you please solve this problem by plugging numbers. Thanks!

'in terms of q' means 'find the price of each battery as a function of q'

i.e. if p = price of each battery, then what is p expressed in q?

Hope that helps.

solving by plugging you can do the following (though this problem is much easier to solve directly than by plugging in numbers):

q=$100

then p=$1.5

then plug in the numbers

lets try A

3q/200 => 3(100)/200 = 1.5 => matches our answer!

but since we're plugging in numbers we can't stop here, we'd have to try all of them to see if any other ones also fit.

In the end, we'll realize that A is the only one that works, and choose A.

The easier way is to solve directly.

100 batteries cost q dollars => cost of one battery = q/100

price of one batter is 50% more than cost => price of one battery = 1.5*cost = 1.5*(q/100)

=> we get that P = (1.5/100)*q = (3/200)*q = answer choice A