Author 
Message 
TAGS:

Hide Tags

Intern
Status: Finance Analyst
Affiliations: CPA Australia
Joined: 10 Jul 2012
Posts: 16
Location: Australia
Concentration: Finance, Healthcare
GMAT 1: 470 Q38 V19 GMAT 2: 600 Q44 V34
GPA: 3.5
WE: Accounting (Health Care)

A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
19 Aug 2013, 19:09
Question Stats:
47% (02:43) correct 53% (02:28) wrong based on 805 sessions
HideShow timer Statistics
A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each? A. 1.5 B. 2.5 C. 3 D. 4.5 E. 5
Official Answer and Stats are available only to registered users. Register/ Login.




Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 9869
Location: Pune, India

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
23 Jun 2014, 20:39
vaishnogmat wrote: A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
A. 1.5 B. 2.5 C. 3 D. 4.5 E. 5 Responding to a pm: Quote: Using the Scale method 40% 50% 100% 15x x Hence (15x)/x = 50/10 I cannot understand how 15 x cups can be equal to 40% of chocolate . where X is the cups of Mixture removed and replaced with Pure Chocolate.
My understanding: The 15 cups are prepared by mistaken proportions of 40% chocolate and 60% Rasberry . Hence when we remove x cups of mixture from 15 cups of Chocolate + Rasberry Mixture , we are left with chocolate equal to 40% of 15x Hence now 40%* ( 15x) Choco will be mixed with x cups of Choco at 100% to obtain choco at 50%
Is this understanding correct?
Will the concentration of chocolate always be at 40% ,in the 15 Cups prepared by mistaken combination , even if we consider 1 cup or 2 cups or x cups of the mixture? Yes, we assume that the mix is homogeneous. Otherwise, we will not be able to solve the question. Look at the question from a different perspective for ease (don't mix it up with algebra): You have 15 cups of sauce with 40% chocolate. You also have unlimited amount of pure chocolate sauce. Now you need to mix these two in such a way that you get total 15 cups of sauce with 50% chocolate. Using scale method: w1/w2 = (100  50)/(50  40) = 5/1 w1  Amount of 40% chocolate sauce w2  Amount of pure chocolate sauce So for every 5 cups of 40% chocolate sauce, we need 1 cup of pure chocolate sauce. This will give us 6 cups of 50% chocolate sauce. But we need 15 cups of 50% chocolate sauce. So we need to mix 5*15/6 = 12.5 cups of 40% chocolate sauce with 1*15/6 = 2.5 cups of pure chocolate sauce. Hence, when we are replacing, we remove 2.5 cups of 40% chocolate sauce and put 2.5 cups of pure chocolate in it. Answer (B) Look at example 1 here: http://www.veritasprep.com/blog/2012/01 ... mixtures/It is very similar to this question.
_________________
Karishma Veritas Prep GMAT Instructor
Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options >




Director
Joined: 14 Dec 2012
Posts: 688
Location: India
Concentration: General Management, Operations
GPA: 3.6

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
19 Aug 2013, 23:34
vaishnogmat wrote: Q) A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
a) 1.5 b) 2.5 c) 3 d) 4.5 e) 5 we have 15 cups os sauce with \(40 %\) choc and \(60 %\) rasb cups of choc = \(0.4*15 = 6\) cups of rasb = \(0.6*15 = 9\) now let say we removed x cup of original mix and replaced with x cups of choc. therefore final number of cups of choc =\(60.4x+x\) now this number of cup should be 50% of total = \(15/2 = 7.5\) therefore \(60.4x+x= 7.5\) on solving \(x= 2.5\) hence B
_________________
When you want to succeed as bad as you want to breathe ...then you will be successfull....
GIVE VALUE TO OFFICIAL QUESTIONS...
GMAT RCs VOCABULARY LIST: http://gmatclub.com/forum/vocabularylistforgmatreadingcomprehension155228.html learn AWA writing techniques while watching video : http://www.gmatprepnow.com/module/gmatanalyticalwritingassessment : http://www.youtube.com/watch?v=APt9ITygGss




Director
Joined: 17 Dec 2012
Posts: 623
Location: India

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
20 Aug 2013, 06:28
vaishnogmat wrote: A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
A. 1.5 B. 2.5 C. 3 D. 4.5 E. 5 1. In 15 cups the proper mix should be 50% melted chocolate and 50% raspberry puree but the actual mix made was 40% melted chocolate and 60% raspberry puree. 2. Raspberry puree should be 10% less and melted chocolate should be 10% more in the mixture. 10% is equal to 1.5 cups i.e., you need to have the net effect of taking 1.5 cups of raspberry puree out of the mixture and adding 1.5 cups of melted chocolate to the mixture. 3.The net effect of taking out 1 cup of mixture and replacing it with 1 cup of melted chocolate is that of taking out 0.6 cup of raspberry puree and adding 0.6 cup of melted chocolate. 4. So to achieve the desired net effect as in (2) we need to take out 1.5/0.6 i.e., 2.5 cups of the mixture and replace it with the same amount of melted chocolate. The answer is therefore 2.5 cups.
_________________
Srinivasan Vaidyaraman Sravna Test Prep http://www.sravnatestprep.comHolistic and Systematic Approach



Director
Joined: 17 Dec 2012
Posts: 623
Location: India

A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
23 Jun 2014, 23:23
s1 0.4*15=6 cups, element 1 and 0.6*15=9 cups, element 2 s2 Remove x cups of the mix i.e., 0.4x cups element 1 and 0.6x cups element 2 s3 Add x cups element 1 The desired ratio of the elements is 1:1 Thus (6  0.4x +x) / (9  0.6x) = 1/1 => x=2.5 cups
_________________
Srinivasan Vaidyaraman Sravna Test Prep http://www.sravnatestprep.comHolistic and Systematic Approach



SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1727
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
24 Jun 2014, 02:23
Chocolate ............. Raspberry ............ Total
6 .............................. 9 ........................ 15
Say "x" quantity is removed; New Equation is..
\(6  \frac{6x}{15}\) .................. \(9\frac{9x}{15}\) ..................... 15x
Whatever the quantity removed, same amount of chocolate is added
\(6  \frac{6x}{15} + x\) ............... \(9  \frac{9x}{15}\) .................. 15  x + x
Addition should be 50% of the total
Equation can be setup in 2 ways:
\(6  \frac{6x}{15} + x = \frac{50}{100} * 15\) ................. (1)
OR
\(9  \frac{9x}{15} = \frac{50}{100} * 15\) ................... (2)
Will got with (2) as it has variable only on one side (Minimal Calculations)
\(\frac{9x}{15} = 7.5\)
x = 2.5
Answer = B



Manager
Joined: 26 Sep 2013
Posts: 182
Concentration: Finance, Economics
GMAT 1: 670 Q39 V41 GMAT 2: 730 Q49 V41

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
21 Nov 2013, 12:46
I just used quick math and started with C)
removing 3 cups, 60% of which is rasp, so you're removing 1.8, leaving you with 7.2 cups, and the remaining 1.2 comes from choco, leaving you with 4.8, adding 3 back in, you end up with too much choco, so it must be a or b. with b, you remove 2.5, 60% of which is rasp, or 1.5, leaving you with 7.5, and the remaining 1 comes from choco, leaving you with 5. Add 2.5 pure choco you get 7.5/7.5, so B) is the answer.
I think sometimes in the time timespan it would take to read, comprehend, figure out a formula, write it down and solve, you could have easily just plugged in the numbers. Remember, the GMAT doesn't know/care if you solved via basic plugin math like I use, or some elegant formula. All that matters is if you got it correct.



Math Expert
Joined: 02 Aug 2009
Posts: 8302

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
07 Jan 2016, 07:03
vaishnogmat wrote: A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
A. 1.5 B. 2.5 C. 3 D. 4.5 E. 5 Hi all, another approach to this Q, which could be slightly easier and less time consuming is.. 15 cups with 40% of choc will mean there are 6 cups of choc.. what was it supposed to be.. 50% or .5*15=7.5 cups.. this is 1.5 cups short..now he is to make up for this 1.5 cups.. if we take out one cup, which includes .4 choc and add one cup of pure choc, the final effect is addn of .6 cup of choc..But we have to make up for 1.5 cups.. if .6 cup requires replacement of one cup,.. 1.5 cup will require 1/.6 *1.5= 2.5 cups..ans B
_________________



CEO
Status: GMATINSIGHT Tutor
Joined: 08 Jul 2010
Posts: 2977
Location: India
GMAT: INSIGHT
WE: Education (Education)

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
12 Nov 2018, 04:30
chanchal1311 wrote: GMATinsight pls send your explanation chanchal1311 Here is my solution Quote: A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
A. 1.5 B. 2.5 C. 3 D. 4.5 E. 5 Current volume = 15 cups Melted chocolate present as of now = 40% of 15 = 6 cups raspberry Puree present as of now = 60% of 15 = 9 cups Let, the volume replaced = x cups raspberry Puree present in x cups = 60% of x = 0.6x cups Since the x cups are being replaced by Pure melted chocolate so the raspberry puree that goes does will NOT come backi.e. Net value of Raspberry puree after replacement of x cups by melted chocolate = 9  0.6x (which should make it 50% of the entire solution as desired)i.e. 9  0.6x = 50% of 15 cups = 7.5 cups i.e. 0.6x = 9  7.5 = 1.5 cups i.e. x = 2.5 cups Answer: Option B
_________________
Prosper!!!GMATinsightBhoopendra Singh and Dr.Sushma Jha email: info@GMATinsight.com I Call us : +919999687183 / 9891333772 Online OneonOne Skype based classes and Classroom Coaching in South and West Delhihttp://www.GMATinsight.com/testimonials.htmlACCESS FREE GMAT TESTS HERE:22 ONLINE FREE (FULL LENGTH) GMAT CAT (PRACTICE TESTS) LINK COLLECTION



Manager
Joined: 06 Jun 2012
Posts: 115

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
20 Aug 2013, 00:43
I misread the question, Again!! Nyways another method 40% 50% \ / 50% / \ 100% 10%
so 50/10 = 15x/x => x =2.5 cups



Math Expert
Joined: 02 Sep 2009
Posts: 59674

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
20 Aug 2013, 02:20
vaishnogmat wrote: A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
A. 1.5 B. 2.5 C. 3 D. 4.5 E. 5 Similar questions to practice: m0772458.htmlacertainbreadrecipecallsforwheatwhiteflourandoat103934.htmlmiguelismixingupasaladdressingregardlessofthe109740.htmlmaliksrecipefor4servingsofacertaindishrequires123239.htmlacertainbreadrecipecallsforwholewheatflourwhite129148.htmlareciperequires212cupsofflour234cupsofsugar152952.htmlwhatistheratioofthenumberofcupsofflourtothe72081.htmlHope it helps.
_________________



SVP
Joined: 06 Sep 2013
Posts: 1545
Concentration: Finance

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
Updated on: 08 Feb 2014, 07:02
vaishnogmat wrote: A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
A. 1.5 B. 2.5 C. 3 D. 4.5 E. 5 Remember he is replacing the mixture by pure chocolate so with every cup X of the mixture he replaces he will pour x cups of pure chocolate. So we have: 6+x2/5x = 93/5x x=2.5 B Hope it helps Cheers! J
Originally posted by jlgdr on 11 Jan 2014, 05:51.
Last edited by jlgdr on 08 Feb 2014, 07:02, edited 1 time in total.



Intern
Joined: 22 Jan 2014
Posts: 3

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
25 Jan 2014, 07:50
SravnaTestPrep wrote: vaishnogmat wrote: A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
A. 1.5 B. 2.5 C. 3 D. 4.5 E. 5 1. In 15 cups the proper mix should be 50% melted chocolate and 50% raspberry puree but the actual mix made was 40% melted chocolate and 60% raspberry puree. 2. Raspberry puree should be 10% less and melted chocolate should be 10% more in the mixture. 10% is equal to 1.5 cups i.e., you need to have the net effect of taking 1.5 cups of raspberry puree out of the mixture and adding 1.5 cups of melted chocolate to the mixture. 3.The net effect of taking out 1 cup of mixture and replacing it with 1 cup of melted chocolate is that of taking out 0.6 cup of raspberry puree and adding 0.6 cup of melted chocolate. 4. So to achieve the desired net effect as in (2) we need to take out 1.5/0.6 i.e., 2.5 cups of the mixture and replace it with the same amount of melted chocolate. The answer is therefore 2.5 cups. Using the same method as SwarnaTestprep, I tried solving this problem using a table. You might find it easy to visualize what is going on when pure/impure cups of the ingredients are added or removed.
Attachments
Screen Shot 20140125 at 15.48.27.png [ 162.52 KiB  Viewed 16763 times ]



Manager
Status: PLAY HARD OR GO HOME
Joined: 25 Feb 2014
Posts: 128
Location: India
Concentration: General Management, Finance
GPA: 3.1

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
01 Nov 2014, 13:42
The best formula ever to solve most of the REMOVE AND REPLACE mixture questions= Suppose a container contains x of liquid from which y units are taken out and replaced by water. After n operations, the quantity of pure liquid = \(x ( 1 \frac{y}{x})^n\) Lets use it here = \(\frac{1}{2}* 15= 7.5\) which is a desired value. Hence, \(7.5 = 9 ( 1  \frac{x}{15})^1\) \(\frac{5}{6}= \frac{15x}{15}\) \(6x = 15\) \(x = 2.5\) P.S = You can use 6 as well for chocolate sauce in this formula. Please Consider KUDOS if my post helped
_________________
ITS NOT OVER , UNTIL I WIN ! I CAN, AND I WILL .PERIOD.



Manager
Joined: 20 Jul 2013
Posts: 51

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
25 Jan 2015, 10:05
russ9 wrote: blueseas wrote: vaishnogmat wrote: Q) A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
a) 1.5 b) 2.5 c) 3 d) 4.5 e) 5 we have 15 cups os sauce with \(40 %\) choc and \(60 %\) rasb cups of choc = \(0.4*15 = 6\) cups of rasb = \(0.6*15 = 9\) now let say we removed x cup of original mix and replaced with x cups of choc. therefore final number of cups of choc =\(60.4x+x\) now this number of cup should be 50% of total = \(15/2 = 7.5\) therefore \(60.4x+x= 7.5\) on solving \(x= 2.5\) hence B Hi, I was with you until " final number of cups of choc =\(60.4x+x\)" After I came up with 6 and 9, i proceeded to divide the options in half. What I mean is, for option B, 2.5  if we removed 2.5, that means that we would remove half of the 2.5 = 1.25 of chocolate and 1.25 of puree. I'm not sure why you removed 40%(although I can see that 40% represents the chocolate percent). Logically, if we remove the sauce, wouldn't we remove equal parts of puree and equal parts of chocolate? Hi, There! I guess I'm a few months too late on this response, but I'll try to give it a go. When we remove cups of the sauce, we're removing parts of both chocolate and puree  according to their respective percentages. In this case: we have 15 cups of sauce. The prompt asks us to remove "X" amount of cups from the sauce, and add the same "X" amount of chocolate  to give us an equal 7.5/7.5 split. We're not splitting the "X" amount. For Choice B, if we take 2.5 out of 15 ... we have 12.5 cups of Sauce: giving us 5 cups of Chocolate and 7.5 cups of Puree (since we have to take 40% choc. and 60% Puree from the sauce) Now, adding the same amount, 2.5 back into the Chocolate, we have the perfect split: 7.5/7.5 ... Hence, B is correct. Now, how did we get there through the method you tried to follow? First of all, let's think logically: we have 15 cups of Sauce, broken down to as you pointed out, 6 Chocolate and 9 Puree. Focus only on the Chocolate. We need to raise its initial value UP to 7.5 by removing cups of the sauce, and replacing the SAME AMOUNT with cups of chocolate. Now, to get 7.5, we need to remove "X" amount of the 15 cups of sauce and MULTIPLY that value by 40%  giving us the chocolate value of the "reduced" sauce value. Just like we earlier with Choice B: (152.5)(2/5) = 5 Then, we need to add the SAME "X" amount back into the chocolate. And, that's how we get this equation: 7.5 = 2/5 (15  X) + X 7.5 = 6  .4X + X 1.5 = .6X X = 2.5 A good problem, for good practice. Hope that helped!



Manager
Joined: 28 Aug 2006
Posts: 242

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
30 Dec 2015, 21:58
vaishnogmat wrote: A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
A. 1.5 B. 2.5 C. 3 D. 4.5 E. 5 Different approach with Ratios that will help to answer with min calculation efforts. Assume that x cups of the sauce is removed. 15 cups contain Choc & Rasp in the ratio 2 : 3  (1) 15  x cups contain Choc & Rasp in the ratio 2 : 3  (2) 15 cups contain Choc & Rasp in the ratio 1 : 1  (3) (After adding x cups of Choc) Since to 15  x cups of sauce we have added pure Choc, the amount of Rasp in 15  x cups and the final 15 cups must be same. Ensure that the ratios also reflect the same. So, in statement (3), change the ratio from 1 : 1 to 3 : 3 15  x cups contain Choc & Rasp in the ratio 2 : 3  (2) 15 cups contains Choc & Rasp in the ratio 3 : 3  (3) Now, from the above two ratios it is clear that Choc changed from 2 parts to 3 parts. So we have added 1 part of Choc which is the value of 'x'. Also, from (3), we have 6 parts as 15 cups and hence 1 part must be 2.5 cups.
_________________



Senior SC Moderator
Joined: 14 Nov 2016
Posts: 1347
Location: Malaysia

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
17 May 2017, 17:57
vaishnogmat wrote: A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
A. 1.5 B. 2.5 C. 3 D. 4.5 E. 5 We've got 9 cups of raspberry and 6 of chocolate. To fix this, we need to remove 1.5 cups of raspberry. But! We can't take out raspberry by itself. It's already mixed with the chocolate. We can only remove the mix. Mix = 60% raspberry, 40% chocolate Every cup of mix we remove = 0.6 cups raspberry + 0.4 cups chocolate 60% of 1 cup = 0.6 cups So each cup of mix gets us 0.6 cups raspberry 0.6 cups of raspberry * (# of cups of mix) = 1.5 cups of raspberry 0.6 * x = 1.5 x = 2.5 We need 1.5 cups raspberry 0.6 * 2.5 = 1.5 So we need to remove 2.5 cups of mix. Answer : B
_________________
"Be challenged at EVERY MOMENT."“Strength doesn’t come from what you can do. It comes from overcoming the things you once thought you couldn’t.”"Each stage of the journey is crucial to attaining new heights of knowledge."Rules for posting in verbal forum  Please DO NOT post short answer in your post! Advanced Search : https://gmatclub.com/forum/advancedsearch/



Intern
Status: Finance Analyst
Affiliations: CPA Australia
Joined: 10 Jul 2012
Posts: 16
Location: Australia
Concentration: Finance, Healthcare
GMAT 1: 470 Q38 V19 GMAT 2: 600 Q44 V34
GPA: 3.5
WE: Accounting (Health Care)

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
20 Aug 2013, 12:02
Bunuel wrote: vaishnogmat wrote: A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
A. 1.5 B. 2.5 C. 3 D. 4.5 E. 5 Similar questions to practice: m0772458.htmlacertainbreadrecipecallsforwheatwhiteflourandoat103934.htmlmiguelismixingupasaladdressingregardlessofthe109740.htmlmaliksrecipefor4servingsofacertaindishrequires123239.htmlacertainbreadrecipecallsforwholewheatflourwhite129148.htmlareciperequires212cupsofflour234cupsofsugar152952.htmlwhatistheratioofthenumberofcupsofflourtothe72081.htmlHope it helps. Bunuel, how would you solve this question using a methodical approach? Thanks.



Intern
Joined: 13 Jul 2012
Posts: 4

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
02 Sep 2013, 10:35
vaishnogmat wrote: A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
A. 1.5 B. 2.5 C. 3 D. 4.5 E. 5 Conentrating only on chocolate. Assuming that one would need to replace x cups of 40% chocolate by 100% chocolate, then (15x)*(5040)=x*(10050), i.e., product of distances (here the number of cups) from the mean concentration (i.e., 50%) of both the mixtures, i.e., the original mixture of 40% concentration of chocolate and pure chocolate respectively would be equal. Simplifying, 15*10=60x. Hence, x=2.5 cups.



Manager
Joined: 12 Sep 2014
Posts: 141
Concentration: Strategy, Leadership
GPA: 3.94

Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
Show Tags
28 Oct 2014, 10:25
I got this wrong, but I definitely understand it.
I think this way is the easiest to think about solving the problem. We need to end up with equal parts of two ingredients. In 15 cups, we need 7.5 cups of each ingredient. So, that means, taking out 1.5 of 9 total cups of the raspberry puree. Let's just compute how many total cups should be removed: 1.5/9 = x/15 or EVEN EASIER: 1/6 = x/15 > x = 2.5




Re: A dessert recipe calls for 50% melted chocolate and 50% rasp
[#permalink]
28 Oct 2014, 10:25



Go to page
1 2
Next
[ 38 posts ]



