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# A drink contains only 7 oz. of soda and 3 oz. of juice. A second drink

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A drink contains only 7 oz. of soda and 3 oz. of juice. A second drink [#permalink]

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02 Jan 2010, 08:01
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A drink contains only 7 oz. of soda and 3 oz. of juice. A second drink that contains only soda and juice is poured into the first. How many oz. of liquid were poured in?

(1) After the second drink is poured in, 40% of the entire beverage is juice.
(2) 30% of the second drink was soda.
[Reveal] Spoiler: OA
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Re: A drink contains only 7 oz. of soda and 3 oz. of juice. A second drink [#permalink]

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02 Jan 2010, 16:36
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IMO C...

Explanation:

Original drink quantity = 7+3 = 10 oz.

Let x quanitity of second drink be added which has J% of juice in it.

Statement 1: After the second drink is poured in, 40% of the entire beverage is juice.

$$0.4 (10+X) = 3 + X*\frac{J}{100}$$which is not sufficient as J and X are unknown.

Statement 2: 30% of the second drink was soda
Given only J% of the second drink as 70% but no % of the new mixture. Hence not sufficient.

Combining 1 & 2, we get the answer as now we have J = 70 in Statement 1..

Hence C....

Please share the OA...

Cheers!
JT
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Re: A drink contains only 7 oz. of soda and 3 oz. of juice. A second drink [#permalink]

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27 Jul 2015, 08:21
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Re: A drink contains only 7 oz. of soda and 3 oz. of juice. A second drink [#permalink]

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29 Oct 2016, 12:22
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: A drink contains only 7 oz. of soda and 3 oz. of juice. A second drink [#permalink]

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13 Nov 2016, 10:25
prasadrg wrote:
A drink contains only 7 oz. of soda and 3 oz. of juice. A second drink that contains only soda and juice is poured into the first. How many oz. of liquid were poured in?

(1) After the second drink is poured in, 40% of the entire beverage is juice.
(2) 30% of the second drink was soda.

this is a weighted average problem , let W1 weight of first drink and w2 weight of 2nd drink and A2 = amount of juice in 2nd drink ( or percent) , WA is the weighted average of both drinks mix and A1 the amount of juice in 2nd drink (or percent)

w1/w2 = (A2-WA)/ (WA-A1), QUESTION ASKS FOR W2

FROM Stem we have A1 = 3/10 , W1 = 10 we need A2 and WA

FROM 1
GIVEN IS WA only .... insuff
from 2
given A2 only ... insuff

both we have A2 and WA and we can solve for w2.................C
Re: A drink contains only 7 oz. of soda and 3 oz. of juice. A second drink   [#permalink] 13 Nov 2016, 10:25
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# A drink contains only 7 oz. of soda and 3 oz. of juice. A second drink

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