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# A family pays \$800 per year for an insurance plan that pays

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Intern
Joined: 17 May 2007
Posts: 6

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A family pays \$800 per year for an insurance plan that pays [#permalink]

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09 Jun 2007, 20:52
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A family pays \$800 per year for an insurance plan that pays 80 percent of the first \$1,000 in expenses and 100 percent of all medical expenses thereafter. In any given year, the total amount paid by the family will equal the amount paid by the plan when the family's medical expenses total

A. \$1,000
B. \$1,200
C. \$1,400
D. \$1,800
E. \$2,200

Rick

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CEO
Joined: 17 May 2007
Posts: 2947

Kudos [?]: 667 [0], given: 210

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09 Jun 2007, 21:02
The answer is B - 1200 dollars.

How much does the family have to pay ?
Insurance cost + 200 dollars of the 1st 1000 dollars in expenses
= 800 + 200 = 1000

now this is equal to the actual money that insurance pays
= 800 of the 1st 1000 + (1000 - x ) {where x is the actual medical expense}
800 + 1000 - x = 1000
x = \$1200.

Kudos [?]: 667 [0], given: 210

Intern
Joined: 17 May 2007
Posts: 6

Kudos [?]: [0], given: 0

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09 Jun 2007, 21:12
Quote:
now this is equal to the actual money that insurance pays
= 800 of the 1st 1000 + (1000 - x ) {where x is the actual medical expense}
800 + 1000 - x = 1000
x = \$1200.

From the equation listed above will you not get 800 as the answer for x?

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CEO
Joined: 17 May 2007
Posts: 2947

Kudos [?]: 667 [0], given: 210

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09 Jun 2007, 23:01
Whoops minor typo , its actually x-1000
so the correct equation is
x-1000 + 800 = 1000
x is 1200 (my notebook had the correct equation thankfully )

What is the OA ?

Kudos [?]: 667 [0], given: 210

09 Jun 2007, 23:01
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