Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 24 May 2017, 02:10

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A farmer has an apple orchard consisting of Fuji and Gala

Author Message
Director
Joined: 10 Feb 2006
Posts: 656
Followers: 3

Kudos [?]: 515 [0], given: 0

A farmer has an apple orchard consisting of Fuji and Gala [#permalink]

### Show Tags

16 Nov 2007, 06:26
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 187, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?

22

33

55

77

88

Solution :

F = Fuji
G = Gala
x = Total no. of trees

x/10 - pollinate

F + x/10 = 187
F = 3x/4 - Pure Figi
3x/4 + x/10 = 187

30x + 4x/40 = 187 * 40
x = 187 * 40 /17 = 220

3/4 * 220 = 54 * 3 = 165 - 187 = 22. --- I'm getting A

Any more takers ??
_________________

GMAT the final frontie!!!.

Manager
Joined: 25 Jul 2007
Posts: 108
Followers: 1

Kudos [?]: 22 [0], given: 0

### Show Tags

16 Nov 2007, 07:09
A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 187, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?

22

33

55

77

88

Solution :

F = Fuji
G = Gala
x = Total no. of trees

x/10 - pollinate

F + x/10 = 187
F = 3x/4 - Pure Figi
3x/4 + x/10 = 187

30x + 4x/40 = 187 * 40
x = 187 * 40 /17 = 220

3/4 * 220 = 54 * 3 = 165 - 187 = 22. --- I'm getting A

Any more takers ??

If the number of pure fuji + number of cross pollinated trees = 187 and the total number of trees = 220. Then isn't the number of pure gala trees = total number of trees - total number of non-gala trees = 220 - 187 = 33 ? Or am i missing something here?
Manager
Joined: 20 Sep 2006
Posts: 58
Followers: 1

Kudos [?]: 18 [0], given: 0

### Show Tags

16 Nov 2007, 07:17
A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 187, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?

22

33

55

77

88

Solution :

F = Fuji
G = Gala
x = Total no. of trees

x/10 - pollinate

F + x/10 = 187
F = 3x/4 - Pure Figi
3x/4 + x/10 = 187

30x + 4x/40 = 187 * 40
x = 187 * 40 /17 = 220

3/4 * 220 = 54 * 3 = 165 - 187 = 22. --- I'm getting A

Any more takers ??

Ans B.

3x/4 + x/10 = 187
x=220

Pure Gala = 220 - 187 = 33

However if I do
Gala = Total - Pure Fuji - Cross poolinated
= Total - 3/4(Total) - 1/10(Total) = 35

So I am not 100% sure of my answer.
Manager
Joined: 25 Jul 2007
Posts: 108
Followers: 1

Kudos [?]: 22 [0], given: 0

### Show Tags

16 Nov 2007, 07:22
saviop wrote:
A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 187, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?

22

33

55

77

88

Solution :

F = Fuji
G = Gala
x = Total no. of trees

x/10 - pollinate

F + x/10 = 187
F = 3x/4 - Pure Figi
3x/4 + x/10 = 187

30x + 4x/40 = 187 * 40
x = 187 * 40 /17 = 220

3/4 * 220 = 54 * 3 = 165 - 187 = 22. --- I'm getting A

Any more takers ??

Ans B.

3x/4 + x/10 = 187
x=220

Pure Gala = 220 - 187 = 33

However if I do
Gala = Total - Pure Fuji - Cross poolinated
= Total - 3/4(Total) - 1/10(Total) = 35

= 220 - (3/4(220)) - 1/10(220)
= 220 - 165 - 22
= 33
Director
Joined: 09 Aug 2006
Posts: 757
Followers: 1

Kudos [?]: 210 [0], given: 0

### Show Tags

16 Nov 2007, 07:32
A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 187, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?

22

33

55

77

88

Solution :

F = Fuji
G = Gala
x = Total no. of trees

x/10 - pollinate

F + x/10 = 187
F = 3x/4 - Pure Figi
3x/4 + x/10 = 187

30x + 4x/40 = 187 * 40
x = 187 * 40 /17 = 220

3/4 * 220 = 54 * 3 = 165 - 187 = 22. --- I'm getting A

Any more takers ??

I'm getting 33 using backsolving.

G= gala F = fuji C = cross
Start w/ choice B, G = 33
F + C = 187 (given)
F + C = Total - Gala
Total - Gala = 187
Total = 187 + 33 = 220
F = 3/4 (220) = 165
C = 187 - (165+33) = 22
C = 10% of total --> given
C = 22 = 10% of 220.
Therefore, B is correct.
VP
Joined: 08 Jun 2005
Posts: 1145
Followers: 7

Kudos [?]: 213 [0], given: 0

### Show Tags

16 Nov 2007, 08:56
Pure Gala ---> (187/0.85)*0.15 = 33

Manager
Joined: 14 Nov 2007
Posts: 62
Followers: 1

Kudos [?]: 3 [0], given: 0

### Show Tags

16 Nov 2007, 13:34
85/100 * x = 187

15/100 x = 187*15/85
= 33

16 Nov 2007, 13:34
Display posts from previous: Sort by