SajjadAhmad wrote:
A farmer sells buckets of onions for $2, buckets of potatoes for $4, and buckets of squash for $5. How many buckets of squash did the farmer sell?
(1) The farmer sold one bucket of onions.
(2) In total, the farmer sold 7 buckets of produce for $33.
Source: McGraw-Hill's GMAT
The equation would be \(2x+4y+5z\)
we have to find z
Statement 1:
Nothing about squash. Insufficient.
Statement 2:
\(2x+4y+5z=33\)
This is in form of even+odd=odd
Odd part is contributed by 5.
But for\(z=1\), \(x+2y=14\)
& \(z=3\),\(x+2y=9\).
z has various values, insufficient
(1)+(2)
\(x=1,\)
So, \(2x+4y+5z=33.\)
\(4y+5z=31\)
for \(z=1, y=\frac{26}{4}\), not an integer.
for \(z=3,y=4\)
\(z=5, y=\frac{6}{4}\) not an integer.
So, z=3. Sufficient. IMO, Option C.
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