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A fence as in fence, the ones we all see has a 42.5 foot

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Eternal Intern
Joined: 07 Jun 2003
Posts: 467
Location: Lone Star State
A fence as in fence, the ones we all see has a 42.5 foot [#permalink]

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17 Jul 2003, 08:13
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A fence as in fence, the ones we all see has a 42.5 foot fence with 1/2 foot wide vertical boards are arranged 3 feet apart. How many vertical boards are needed for the entire fence?

The trick I think the connector between each fence but no length is given!

Pretty difficult, I would say.
SVP
Joined: 03 Feb 2003
Posts: 1604

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17 Jul 2003, 10:06
Let us draw a picture

* is a stick
_ is an in-between foot

Thus, the fence is:

*_ _ _ *_ _ _ * _ _ _ * _ _ _ and so on

If X is the number of sticks, then X-1 is the number of in-between three-feet sections.

Finally, X*1/2+(X-1)3=42.5, where X=13
Manager
Joined: 07 Jul 2003
Posts: 56

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17 Jul 2003, 10:33
stolyar wrote:
Let us draw a picture

* is a stick
_ is an in-between foot

Thus, the fence is:

*_ _ _ *_ _ _ * _ _ _ * _ _ _ and so on

If X is the number of sticks, then X-1 is the number of in-between three-feet sections.

Finally, X*1/2+(X-1)3=42.5, where X=13

Ans=13

I got the same answer but I actually drew the picture before I got it. Could you explain your formula. I didnt understand the x-1 bit. Please elobrate.
_________________

Attain Moksha

Eternal Intern
Joined: 07 Jun 2003
Posts: 467
Location: Lone Star State

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17 Jul 2003, 10:57
Are you Hindu, attain Moshka!

An example of using X and X -2 is
I play two games and win 50 percent and I win 25 percent of remainder. Clearly, the remaining games has to be greater than two. Hence, x -2.

But, in this case I really don't see how Stolyar applied it:
SATGATES   [#permalink] 17 Jul 2003, 10:57
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