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A five-student committee must be formed to discuss and plan

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Manager
Joined: 14 Mar 2007
Posts: 235

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A five-student committee must be formed to discuss and plan [#permalink]

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24 May 2007, 10:54
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A five-student committee must be formed to discuss and plan the development of the school’s sporting program. Knowing that each of these five students must be chosen from a group of 10 students, then the possible number of choices is:

(A) 360
(B) 180
(C) 21600
(D) 252
(E) 210

Last edited by andrehaui on 24 May 2007, 11:17, edited 1 time in total.

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VP
Joined: 08 Jun 2005
Posts: 1144

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24 May 2007, 11:22
Andrehaui - you really like this question !!

http://www.gmatclub.com/phpbb/viewtopic.php?t=45762

C(10,5) = 252 , answer (D)

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Manager
Joined: 14 Mar 2007
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24 May 2007, 14:10
Sorry mate I got stuck on this one, but when I put my brain to work I found it really simple and I forgot I've posted it in the past. will try to do not make it happen again.

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VP
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24 May 2007, 14:19
andrehaui wrote:
Sorry mate I got stuck on this one, but when I put my brain to work I found it really simple and I forgot I've posted it in the past. will try to do not make it happen again.

I was only amused by your posts , that's all - I hope I didn't offended you

you can post whatever you want - we are here to help , not to judge !

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Intern
Joined: 20 Apr 2007
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How do you solve this equation [#permalink]

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24 May 2007, 14:59
Can you please list the solution to the equation?

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Manager
Joined: 18 Sep 2006
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24 May 2007, 22:22
A five-student committee must be formed to discuss and plan the development of the school’s sporting program. Knowing that each of these five students must be chosen from a group of 10 students, then the possible number of choices is:

(A) 360
(B) 180
(C) 21600
(D) 252
(E) 210

Solution:
This is a simple combinatorial problem. you have to find out the total number of ways a committee can be formed. The answer is 10C5 as we are choosing 5 people out of a total of 10 (without any order).
So 10C5 = 10!/(10-5)!*5! = 252

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Manager
Joined: 14 Mar 2007
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25 May 2007, 10:01
No problem Killer, don't get amused. We are so focused trying to solve gmat stuff, that sometimes the record machine gets into a state.....

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Director
Joined: 12 Jun 2006
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02 Jun 2007, 12:36
It wasn't clear to me whether they're asking for total # of committees or the total # of students. What made you go with the # of committees? Thankfully, 10*9*8*7*6 wasn't one of the choices.

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VP
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02 Jun 2007, 12:45
ggarr wrote:
It wasn't clear to me whether they're asking for total # of committees or the total # of students. What made you go with the # of committees? Thankfully, 10*9*8*7*6 wasn't one of the choices.

This is a very standard combination question. After you solve a bunch of those questions, the answer becomes obvious.

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02 Jun 2007, 12:45
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