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# A frame of uniform 2-inch width surrounds a square picture of area 25.

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Math Expert
Joined: 02 Sep 2009
Posts: 52971
A frame of uniform 2-inch width surrounds a square picture of area 25.  [#permalink]

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07 Sep 2018, 00:38
00:00

Difficulty:

35% (medium)

Question Stats:

60% (00:59) correct 40% (01:23) wrong based on 18 sessions

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A frame of uniform 2-inch width surrounds a square picture of area 25. What is the area of the frame?

A. 40
B. 50
C. 56
D. 72
E. 81

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Re: A frame of uniform 2-inch width surrounds a square picture of area 25.  [#permalink]

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07 Sep 2018, 01:54
1
Bunuel wrote:
A frame of uniform 2-inch width surrounds a square picture of area 25. What is the area of the frame?

A. 40
B. 50
C. 56
D. 72
E. 81

let, Side of square picture = a
Area of square picture = a^2 = 25
i.e. a = 5
Side of bigger square = side of picture + width of frame on both sides of picture = 5+2+2 = 9
Area of frame = Area of bigger square = area of smaller square = (5+2+2)^2 - 5^2 = 81-25 = 56

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Re: A frame of uniform 2-inch width surrounds a square picture of area 25.   [#permalink] 07 Sep 2018, 01:54
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# A frame of uniform 2-inch width surrounds a square picture of area 25.

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