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# A furniture store sells only two models or desks, model A and model B

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Re: A furniture store sells only two models or desks, model A and model B [#permalink]
carcass wrote:
A furniture store sells only two models or desks, model A and model B The selling price of model A is $120, which is 30 percent of the selling price of model B If the furniture store sells 2,000 desks, $$\frac{3}{4}$$ of which are model B, what is the furniture store's total revenue from the sale of desks? (A)$114,000

(B) $186,000 (C)$294,000

(D) $380,000 (E)$660,000

(the price of model B)*3/10 = $120; (the price of model B) =$400.

Out of 2000 desks $$\frac{3}{4}*2000=1500$$ were model B and the remaining 500 were model A.

Total revenue = 120*500 + 400*1500 = $660,000. Answer: E. Target Test Prep Representative Joined: 04 Mar 2011 Status:Head GMAT Instructor Affiliations: Target Test Prep Posts: 3036 Own Kudos [?]: 6663 [0] Given Kudos: 1646 Re: A furniture store sells only two models or desks, model A and model B [#permalink] Expert Reply carcass wrote: A furniture store sells only two models or desks, model A and model B The selling price of model A is$120, which is 30 percent of the selling price of model B If the furniture store sells 2,000 desks, $$\frac{3}{4}$$ of which are model B, what is the furniture store's total revenue from the sale of desks?

(A) $114,000 (B)$186,000

(C) $294,000 (D)$380,000

(E) $660,000 We are given that the selling price of model A is$120, which is 30% of the selling price of model B. Thus, the selling price of model B is:

(0.3)B = 120

B = 120/0.3 = \$400

We are also given that (3/4)(2,000) = 1500 model B desks were sold, and thus 2,000 - 1500 = 500 model A desks were sold.

Therefore, the total revenue for the desks is 120 x 500 + 400 x 1500 = 60,000 + 600,000 = 660,000 dollars.

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Re: A furniture store sells only two models or desks, model A and model B [#permalink]
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Re: A furniture store sells only two models or desks, model A and model B [#permalink]
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