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# A grocer bought 24Kg of coffee beans at price X. After a

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Manager
Joined: 31 Dec 2003
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A grocer bought 24Kg of coffee beans at price X. After a [#permalink]

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01 Sep 2004, 09:26
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14. A grocer bought 24Kg of coffee beans at price X. After a while one third of the stock got spoiled so he sold the rest for 200\$ per Kilo and made a total profit of twice the cost. What must be price X?

(a) 66 2/3\$.
(b) 50 1/3\$.
(c) 48 1/6\$.
(d) 33 1/3\$.
(e) 24 1/2\$.

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Director
Joined: 20 Jul 2004
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01 Sep 2004, 09:42
Original price = 24X
Spoiled = 8Kg, Rest = 16Kg
Sale Price = 16(200), Profit = 16(200)-24X

16(200)-24X = 2(24X)
X = 400/9 = 44 4/9
I dont see this as an answer choice

Either,
The question sd read "made a total profit equal to the cost.", then (A). 66 2/3\$. Also, I guess, the stem sd be "A grocer bought 24Kg of coffee beans at price X/Kg"
Or
I am missing something too easy due to loss of sleep.

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Manager
Joined: 02 Apr 2004
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01 Sep 2004, 14:21
Well,

I got also \$44 as answer.

When I use as cost only the cost of the sold goods which is 16 kg then I come to solution 66,66. But I doubt we only may calculate the cost of goods sold, because this will not reflect the total cost X when he bought the 24 kilograms of coffee.

Regards,

Alex

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GMAT Club Legend
Joined: 07 Jul 2004
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01 Sep 2004, 19:54
24kg of beans -- \$24x
2/3(24) = 16kg sold, -- \$200 per kg

Profit = 200(16) - 24x = 48x
x = \$44

I don't like this question for one big reason: It said 24kg beans at price X. My initial interpretation is 24kgs cost \$x dollars. However, it turned out instead it meant 24kg for x dollars per kg

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Manager
Joined: 31 Dec 2003
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02 Sep 2004, 00:07
The answer is not matching any of the answer choices. Even i got that ans as 44 4/9.
Thanks.

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02 Sep 2004, 00:07
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