Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

A hiker walking at a constant rate of 4 miles per hour is pa [#permalink]

Show Tags

09 Nov 2010, 07:01

4

This post received KUDOS

18

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

85% (hard)

Question Stats:

59% (02:05) correct
41% (01:38) wrong based on 536 sessions

HideShow timer Statistics

A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 20 miles per hour. the cyclist stops & waits for the hiker 5 min after passing her while the hiker continues to walk at her constant rate. how many minutes must the cyclist wait until the hiker catches up

a hiker walking at a constant rate of 4 miles per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 20 miles per hour. the cyclist stops & waits for the hiker 5 min after passing her while the hiker continues to walk at her constant rate. how many minutes must the cyclist wait until the hiker catches up a 6 2/3 b 15 c 20 d 25 e 26 2/3

i am getting 25 how it is 20

In 1/12 hours (5 minutes) after the hiker is passed by the cyclist the distance between them will comprise \((20-4)*\frac{1}{12}=\frac{4}{3}\) miles (note that during these 5 minute hiker walks too, so their relative rate is 20-4 miles per hour). The hiker thus will need \(\frac{\frac{4}{3}}{4}=\frac{1}{3}\) hours, or 20 minutes to catch up.

Hiker's speed : Cyclist's speed = 4 : 20 = 1 : 5 To cover the same distance, Time taken by Hiker : Time taken by Cyclist = 5 : 1

(If distance is same, speed is inversely proportional to time)

If cyclist took 5 mins, Hiker will take 25 mins. So she will need another 20 mins. (When cyclist was covering the distance in 5 mins, the Hiker was also walking for those 5 mins)
_________________

Re: A hiker walking at a constant rate of 4 miles per hour is pa [#permalink]

Show Tags

14 Oct 2013, 07:39

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: A hiker walking at a constant rate of 4 miles per hour is pa [#permalink]

Show Tags

15 Oct 2013, 20:23

anilnandyala wrote:

A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 20 miles per hour. the cyclist stops & waits for the hiker 5 min after passing her while the hiker continues to walk at her constant rate. how many minutes must the cyclist wait until the hiker catches up

A. 6 2/3 B. 15 C. 20 D. 25 E. 26 2/3

The cyclist is traveling at a pace of 1 mile every 3 minutes. The hiker is traveling at a pace of 1 mile every 15 minutes.

The cyclist passes the hiker, and then 5 minutes later stops, so they are \(\frac{5}{3}\) of a mile from the point they passed the hiker. The hiker is \(\frac{1}{3}\)of a mile past the spot where they were passed. \(\frac{5}{3}\) - \(\frac{1}{3}\) = \(\frac{4}{3}\)of a mile, this is how far ahead the cyclist is from the hiker while they wait. since the hiker takes 15 minutes per mile, it will take \(\frac{4}{3}\)*15=\(\frac{60}{3}\)=20 minutes to catch up to the cyclist.

Re: A hiker walking at a constant rate of 4 miles per hour is pa [#permalink]

Show Tags

09 Dec 2014, 21:48

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: A hiker walking at a constant rate of 4 miles per hour is pa [#permalink]

Show Tags

07 Aug 2015, 02:51

walking guy's speed in miles/min=4/60=1/15. guy in the cycle=20/60=1/3. So it will be = 1/3-1/15=4/3 thats the speed of the cyclist. now how time will it take to cover 4/3 for the walking guy= 4/3/1/15=20

Re: A hiker walking at a constant rate of 4 miles per hour is pa [#permalink]

Show Tags

31 Aug 2015, 09:46

According to my understanding, when moving in same direction, time taken to chatch is represented by - Initial Diference Btwn them/ Difference of their speeds. And When in opposite direction, time taken to meet is represented by - Initial difference btwn then/ Sum of their speeds.

Since they are moving in same direction, the equation is (4/3)/16 * 60, (4/3)- Distance Btwn them. 16- Diference in their speeds (as they are moving in same direction) 60- converting Hrs into mins. which comes out to be 5.

Re: A hiker walking at a constant rate of 4 miles per hour is pa [#permalink]

Show Tags

09 Oct 2016, 22:45

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Best Schools for Young MBA Applicants Deciding when to start applying to business school can be a challenge. Salary increases dramatically after an MBA, but schools tend to prefer...

Marty Cagan is founding partner of the Silicon Valley Product Group, a consulting firm that helps companies with their product strategy. Prior to that he held product roles at...