gmac25 wrote:
A home owner must pick between paint A, which costs $6.00 per liter, and paint B, which costs $4.50 per liter.Paint B takes one third longer to apply than paint A. If the home owner must pay the cost of labor at the rate of $36 per hour, which of the two paints will be cheaper to apply???
1> The ratio of the area covered by one liter of paint A to the area covered by one liter of paint B is 4:3.
2> Paint A will require 40 liters of paint and 100 hours of labor.
Ian / Karishma
Your opinion on this one please? I think the first ratio is enough to answer the question
From statement 1It is actually the ratio of quantity of paint A used : quantity of paint B used = 3:4
If a = quantity of paint A used
b = quantity of paint B used
t1 = time required to apply paint A
t2 = time required to apply paint B
We are given that t2 = 4/3 or t2 = 1.33t1
and
a = 3/4 b = 0.75 b
The question becomes is 6a + 36 t1 < 4.5b + 36 t2
Or 6 * 0.75b + 36t1 < 4.5b + 36 t2
4.5b + 36t1 < 4.5b + 36t2
or The question becomes - Is t1 < t2 ? We know that this is true. Sufficient
From statement 2We don't know the quantity of paint B used. Insufficient.
Answer A