QZ wrote:
A juice company is creating a new fruit punch that is 60% orange juice, 25% grape juice, and 15% apple juice by weight. If the cost for the company is x cents per kg for orange juice, y cents per kg for grape juice, and z cents per kg for apple juice, is the cost of k kg of the fruit punch more than d dollars?
1. \(12x+5y+3z >\) \(\frac{2000d}{k}\)
2. \(10d\) \(=\)\(2^\)\(\sqrt{3x}\) \(=\) \(\sqrt{5y}\)\(=\)\(\sqrt{3z}\)\(=\) \(\frac{100}{k}\)
60% orange juice, 25% grape juice, and 15% apple juice by weight.
Means per kg cost = 0.6x+0.25y+0.15z.... is it >100d/k..
So 0.6x+0.25y+0.15z>100d/k.....
\(12x+5y+3z>\frac{20*100d}{k}\)
Let's see what each statement tells us..
Statement I tells us exactly that..
Sufficient
Second statement tells us 12x=5y=3z=10d*10d..
Therefore 12x+5y+3z=3*10d*10d=3*10d*100/k=3000d/k which is >2000d/k
Ans YES
Sufficient
D
"Second statement tells us 12x=5y=3z=10d*10d..
Therefore 12x+5y+3z=3*10d*10d=3*10d*100/k=3000d/k which is >2000d/k"