SajjadAhmad wrote:
A magazine stand owner sells cups of coffee, newspapers, and packs ofgum. Compared to the number of cups of coffee he sells, he sells twice as many packs of gum, and three times as many newspapers. If he charges $1.25 for a cup of coffee, $.50 for a newspaper, and $.35 for a pack of gum, and sells no other items, which of the following could be the amount of his total gross sales on a given day?
I.$345.00
II.$58.65
III.$22.15
A. I only
B. I + II only
C. I + III only
D. II and III only
E. I, II and III only
We can let the number of packs of gum = g, the number of newspapers = n, and the number of cups of coffee = c, and create the equations:
2c = g
and
3c = n
We need to determine the value of:
1.25c + 0.5n + 0.35g
Substituting, we have:
1.25c + 0.5(3c) + 0.35(2c)
1.25c + 1.5c + 0.7c
3.45c = ?
Now let’s check which Roman numerals is an integer multiple of 3.45.
I.$345.00
Since 345/3.45 = 100, we see that I could be the total gross sales.
II.$58.65
Since 58.65/3.45 = 17, we see that II could be the total gross sales.
III.$22.15
Since 22.15/3.45 = 6.42, we see that III could NOT be the total gross sales.
Answer: B
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