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Re: A man buys some shirts and some ties. The shirts cost $7 each and the [#permalink]
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Bunuel wrote:
A man buys some shirts and some ties. The shirts cost $7 each and the ties cost $3 each. If the man spends exactly $81 and buys the maximum number of shirts possible under these conditions, what is the ratio of shirts to ties?

(A) 5:3

(B) 4:3

(C) 5:2

(D) 4:l

(E) 3:2


We can create the equation:

7S + 3T = 81

7S = 81 - 3T

7S = 3(27 - T)

S = 3(27 - T)/7

The greatest value of S will be obtained when T is as small as possible. The smallest value of T which produces a number divisible by 7 after substitution is 6, so when T is 6 we have:

S = 3(21)/7 = 9

So, the ratio of S to T is 9 : 6 = 3 : 2.

Answer: E
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Re: A man buys some shirts and some ties. The shirts cost $7 each and the [#permalink]
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As total money spend is 81, and person buy max shirts, so we can start calculating with highest shirts possible less than $81 with tie,
Lowest multiple of 7 less than 81 is 77, so shall start with that.
7*11 + tie = 81, 77+3 < 81, so 11 not possible, as tie value is 3, $1 is left
7*10 + tie = 81 , 70+ 3*3 < 81, $2 is left, so 10 cannot be no of shirts

7*9 + tie = 81 , tie = 81-63 =18,
Tie value $3, So total tie would be = 18/3 =6
Hence shirts can be 9 and tie 3
9/3 = 3:2
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Re: A man buys some shirts and some ties. The shirts cost $7 each and the [#permalink]
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Bunuel wrote:
A man buys some shirts and some ties. The shirts cost $7 each and the ties cost $3 each. If the man spends exactly $81 and buys the maximum number of shirts possible under these conditions, what is the ratio of shirts to ties?

(A) 5:3

(B) 4:3

(C) 5:2

(D) 4:l

(E) 3:2



A basic equation can be formed as below...no of shirts be S, no of ties be T
7S+3T=81
=> 7S=3(27-T)
=> 27-T has t be multiple of 7. To maximize S, minimise T ,

Minimum T cab be 6 so that 27-T ie, 21 is multiple of 7.

=> S=9 & T=6
=> S:T = 3:2

E
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Re: A man buys some shirts and some ties. The shirts cost $7 each and the [#permalink]
7S + 3T = 81 --> 3T = 81 - 7S --> T = 27 - (7S)/3.
Now, because T must be an integer, S must be a multiple of 3. Also, we have the maximum of S = 11 (because 7.12 = 84 > 81) --> S = 9 --> T = 27 - 21= 6.
So S:T = 9:6 = 3:2 (E)
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Re: A man buys some shirts and some ties. The shirts cost $7 each and the [#permalink]
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