VeritasKarishma wrote:
Responding to a pm:
A man cheats while buying as well as while selling. While buying he takes 10% more than what he pays for and while selling he gives 20% less than what he claims to. Find the profit percent, if he sells at 9.09% below the cost price of the claimed weight.
Options:
A. 19.81%
B. 20%
C. 37.5%
D. 25%
E. 37.5%
In weight questions, try to go one step at a time.
Say the man buys 100 pounds for $100. But he cheats and takes 110 pounds. This means HIS cost price is $10/11 per pound.
While giving 100 pounds, he actually gives only 80 pounds and charges 9.09% less i.e. 1/11 less than the cost price of 100 pounds which is $100. So he sells at 10/11 * 100 = 1000/11
HIS cost price for 80 pounds = 10/11 * 80 = 800/11
HIS selling price for 80 pounds = 1000/11
Profit = (1000/11 - 800/11)/800/11 * 100 = 25%
If anyone is uncomfortable with Fractions.
You see 20 % then you should understand 80% of x
Hence, take such num's as 80 Units, 10 per unit ;\( 80*10 = 800 = C.P \)
He gets 10% Extra : He gets 88 units.
Now he sells 20% less. that means he
SAYS he is giving 10 units and gives 8
so No of units he can sell = 88*10/8 = 110
he sells at 9.09 lesser than CP .
CP/unit = 10 , SP/unit = 9.1 ( Options A, B are so close that rounding off looks risky )
so he sells 110 units at 9.1 per unit
Total revenue he got 110*9.1 = 999
so profit = \(\frac{(999-800 )*100}{ 800}\) = 25%
Or else,
sp/cp = \(110/100*100/80*10/11= 10/8\)
Profit % = \(\frac{2}{8}\)