It is currently 24 Nov 2017, 01:16

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A manikin stands on a conic sugar loaf with height of 12 cm.

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Director
Joined: 17 Dec 2005
Posts: 544

Kudos [?]: 40 [0], given: 0

Location: Germany
A manikin stands on a conic sugar loaf with height of 12 cm. [#permalink]

### Show Tags

26 Jan 2006, 03:38
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A manikin stands on a conic sugar loaf with height of 12 cm. If he runs down the sugar loaf at a constant speed of one centimetre per second, approximately how long will it last till he reaches table the loaf is standing on.

4,5,6,7 or 8 seconds?

To clarify:
conical is meant to be isoceles

Last edited by allabout on 26 Jan 2006, 03:51, edited 1 time in total.

Kudos [?]: 40 [0], given: 0

Director
Joined: 10 Oct 2005
Posts: 713

Kudos [?]: 26 [0], given: 0

Re: PS - general concept training - mixed [#permalink]

### Show Tags

26 Jan 2006, 03:45
A manikin stands on a conic sugar loaf with height of 12 cm. If he runs down the sugar loaf at a constant speed of one centimetre per second, approximately how long will it last till he reaches table the loaf is standing on.

4,5,6,7 or 8 seconds?

allabout are you sure that there is no typo?I have a feeling that some info is missing))
_________________

IE IMBA 2010

Kudos [?]: 26 [0], given: 0

VP
Joined: 20 Sep 2005
Posts: 1016

Kudos [?]: 38 [0], given: 0

### Show Tags

26 Jan 2006, 12:43
My 200th post...I never new that I would last this long

Something is missing here. How long does it last ?

Since the conical is isoceles, it has to travel a distance equal to the hyptoneuse 12*sqrt(2) which gives around 16.8 seconds. To find the answer we need the decay rate.

Kudos [?]: 38 [0], given: 0

Director
Joined: 17 Dec 2005
Posts: 544

Kudos [?]: 40 [0], given: 0

Location: Germany

### Show Tags

26 Jan 2006, 14:52
That's the question I think of, nothing more

The answers given were wrong, sorry for that inconvenience.

The height is 12

the hypotenuse is 12/sqrt 3 * 2 = ~ 14 cm

Thus it lasts ~14 seconds till he reaches the base of the loaf. Maybe the "sugar loaf" isn't the same in Germany as elsewhere.
Attachments

Unbenannt.JPG [ 4.52 KiB | Viewed 580 times ]

Kudos [?]: 40 [0], given: 0

CEO
Joined: 20 Nov 2005
Posts: 2892

Kudos [?]: 336 [0], given: 0

Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008

### Show Tags

26 Jan 2006, 15:45
I don't agree with this.
In the figure below:

Height = CD = 12 cm
AB could be anything. Say AB = 10 then BC or AC = 13 and may be anything depending on the value of AB.

Please correct me if I am wrong...
Attachments

Cone.jpg [ 4.14 KiB | Viewed 573 times ]

_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Kudos [?]: 336 [0], given: 0

Director
Joined: 10 Oct 2005
Posts: 713

Kudos [?]: 26 [0], given: 0

### Show Tags

26 Jan 2006, 22:49
That's the question I think of, nothing more

The answers given were wrong, sorry for that inconvenience.

The height is 12

the hypotenuse is 12/sqrt 3 * 2 = ~ 14 cm

Thus it lasts ~14 seconds till he reaches the base of the loaf. Maybe the "sugar loaf" isn't the same in Germany as elsewhere.

allabout please explain how did you figure out that hypotenuse is 12/sqrt 3 * 2 without knowing the lenght of second side?
As ps_dahiya said befor it could be anything
_________________

IE IMBA 2010

Kudos [?]: 26 [0], given: 0

Director
Joined: 17 Dec 2005
Posts: 544

Kudos [?]: 40 [0], given: 0

Location: Germany

### Show Tags

27 Jan 2006, 01:15
Since the triangle is isoceles (not equilateral), half of it is a 1:sqrt3:2 triangle

Accordingly you can divide the height by sqrt3.

Am I wrong?

Kudos [?]: 40 [0], given: 0

27 Jan 2006, 01:15
Display posts from previous: Sort by

# A manikin stands on a conic sugar loaf with height of 12 cm.

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.