GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 07 Dec 2019, 06:53

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# A milkman mixes water and milk in a container in the ratio

Author Message
TAGS:

### Hide Tags

Manager
Joined: 13 Aug 2018
Posts: 55
A milkman mixes water and milk in a container in the ratio  [#permalink]

### Show Tags

23 Mar 2019, 06:59
2
1
13
00:00

Difficulty:

95% (hard)

Question Stats:

34% (03:35) correct 66% (03:29) wrong based on 35 sessions

### HideShow timer Statistics

A milkman mixes water and milk in a container in the ratio of 2 : 5, respectively. Initially, he sells the mixture at \$30 per liter. After selling 70 liters of mixture, he mixes another 20 liters of water and then ratio of water and milk becomes 8 : 15, respectively. The new mixture is sold by the milk man at the rate of \$25 per liter. If cost of milk is \$27 per liter then find the profit of milkman in the whole transaction?

a. \$2050
b. \$2500
c. \$2950
d. \$2450
e. \$3300

Posted from my mobile device
Intern
Joined: 27 Nov 2018
Posts: 30
Re: A milkman mixes water and milk in a container in the ratio  [#permalink]

### Show Tags

23 Mar 2019, 18:46
1
1
Original mixture: W/M=2/5
Sold 70L - 20L water, 50L milk

New mixture: add 20L water into mixture
(W-20+20)/(M-50) = 8/15
Original mixture: W=80, M=200
New mixture: W=80, M=150, Total=230

Profit=Revenue-cost
70x30 + 230x25 - 27x200 = 2450

D
Manager
Joined: 09 Nov 2015
Posts: 153
Re: A milkman mixes water and milk in a container in the ratio  [#permalink]

### Show Tags

09 Apr 2019, 01:10
1
1
The quantity of milk in the 70 liters of the original mixture (M1) that the milkman sold at \$30/L is 50 liters. So his cost for was \$(50*27)=\$1350 and his revenue was \$(70*30)=\$2100 for the 1st transaction. So his profit for the first transaction (P1) was \$(2100 - 1350)=\$750.

Let the remaining quantity of M1 be 7x liters of which the quantities of water and milk are obviously 2x and 5x liters respectively. When 20 liters of water is added to this 7x liters of M1, the quantity of milk increases to (2x+20) liters so the ratio of water to milk in this new mixture (M2) becomes (2x+20)/5x which we are told is equal to 8/15. So, (2x+20)/5x=8/15-----> x=30.
Qty of M2=7x+20=230 liters.
Revenue from selling M2=230*25=\$5750
Cost of M2=(Qty Of milk in M2)*27=5*30*27=\$4050
Profit from 2nd transaction (P2) is \$(5750-4050)=\$1700

Total profit: P1+P2 \$(750+1700)= \$2450. Ans:D
Re: A milkman mixes water and milk in a container in the ratio   [#permalink] 09 Apr 2019, 01:10
Display posts from previous: Sort by