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A nation’s population triples every 100 years. If the population was
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07 Jan 2022, 08:15
07 Jan 2022, 08:15
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A nation’s population triples every 100 years. If the population was 100,000 in the year 1200, in what year was the population 72,900,000?
(A) 600
(B) 1700
(C) 1800
(D) 1900
(E) 2000
(A) 600
(B) 1700
(C) 1800
(D) 1900
(E) 2000
Quant Chat Moderator
Joined: 22 Dec 2016
Posts: 3128
Given Kudos: 1859
Location: India
Concentration: Strategy, Leadership
A nation’s population triples every 100 years. If the population was
[#permalink]
07 Jan 2022, 09:24
07 Jan 2022, 09:24
Given
A nation’s population triples every 100 years.
Thus the percentage at which the population grows = 200%
Let us assume that every t represents one block of 100 years.
Thus -
\(72,900,000 = 100,000 * (1 + \frac{200}{100})^ t \)
Dividing the equation by 100,000 on both the sides and reducing the fractions we get -
\(729 = (1 + 2)^ t \)
\(27^2 = 3^ t \)
\(3^{2*3} = 3^ t \)
Therefore t = 6
We had assumed 't' to be a block of 100 years, so 6 represents 600 years.
Year in which the population becomes \(729*10^5 \)
= 1200 + 600 = 1800
A nation’s population triples every 100 years.
Thus the percentage at which the population grows = 200%
Let us assume that every t represents one block of 100 years.
Thus -
\(72,900,000 = 100,000 * (1 + \frac{200}{100})^ t \)
Dividing the equation by 100,000 on both the sides and reducing the fractions we get -
\(729 = (1 + 2)^ t \)
\(27^2 = 3^ t \)
\(3^{2*3} = 3^ t \)
Therefore t = 6
We had assumed 't' to be a block of 100 years, so 6 represents 600 years.
Year in which the population becomes \(729*10^5 \)
= 1200 + 600 = 1800
Re: A nations population triples every 100 years. If the population was
[#permalink]
21 Jun 2023, 13:33
21 Jun 2023, 13:33
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