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Manager
Joined: 23 Mar 2008
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24 Jun 2008, 13:13
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A) 16
B) 32
C) 41
D) 54
E) 68

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Intern
Joined: 05 Nov 2007
Posts: 35

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24 Jun 2008, 13:30

A) 16
B) 32
C) 41
D) 54
E) 68"

I get E.
there are 5 different colors, and the pattern starts with red.
Every multiple of 5 the beads repeat, so red = 1, 6, 11, and white = 3, 8, 13, 18, etc.

Remainder of 16/5 = 1 therefore red
Remainder of 32/5 = 2 therefore green
Remainder of 41/5 = 1 therefore red
Remainder of 54/5 = 4 therefore blue
Remainder of 68/5 = 3 therefore white

E

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Intern
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24 Jun 2008, 14:19
gmatatouille wrote:

there are 5 different colors, and the pattern starts with red.
Every multiple of 5 the beads repeat, so red = 1, 6, 11, and white = 3, 8, 13, 18, etc.

Remainder of 16/5 = 1 therefore red
Remainder of 32/5 = 2 therefore green
Remainder of 41/5 = 1 therefore red
Remainder of 54/5 = 4 therefore blue
Remainder of 68/5 = 3 therefore white

E

That way is awesome. The way I did it was by thinking there are 5 beads, and you wanted to end on the third bead, therefore the sequence is 5x+3 = N. Therefore, x cannot have a fraction because the sequence ends.

5x+3= 16 (R3)
5x+3= 32 (R4)
5x+3= 41 (R3)
5x+3= 54 (R4)
5x+3= 68 no remainder, therefore white.

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Intern
Joined: 05 Nov 2007
Posts: 35

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24 Jun 2008, 15:11
Essentially the same method, you just put a formula to it

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Current Student
Joined: 28 Dec 2004
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Location: New York City
Schools: Wharton'11 HBS'12

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24 Jun 2008, 15:53
E for me too..

5N+3=X..

5n=x-3..which ever is evenly divisible by 5..is the ans

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Director
Joined: 14 Aug 2007
Posts: 726

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24 Jun 2008, 23:33
puma wrote:

A) 16
B) 32
C) 41
D) 54
E) 68

E,

Among the answers only N=68 satisfies 5*x + 3

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Re: necklace   [#permalink] 24 Jun 2008, 23:33
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