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# A nickel, a dime, and 2 quarters are arranged along a side

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Manager
Status: Still Struggling
Joined: 03 Nov 2010
Posts: 132

Kudos [?]: 106 [0], given: 8

Location: India
GMAT Date: 10-15-2011
GPA: 3.71
WE: Information Technology (Computer Software)
A nickel, a dime, and 2 quarters are arranged along a side [#permalink]

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03 Nov 2010, 05:21
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Hi guys...
i had a problem and needed an insight on the same:

A nickel, a dime, and 2 quarters are arranged along a side of the table. if the quarter and the dime have to face heads up and nickel can face either heads up or tails up, how many different arrangements of coins are possible?

The answer says 4!/2!) * 2!

Can somebody please explain me how to arrive to this ans?

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Re: A nickel, a dime, and 2 quarters [#permalink]

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03 Nov 2010, 07:29
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krishnasty wrote:
Hi guys...
i had a problem and needed an insight on the same:

A nickel, a dime, and 2 quarters are arranged along a side of the table. if the quarter and the dime have to face heads up and nickel can face either heads up or tails up, how many different arrangements of coins are possible?

The answer says 4!/2!) * 2!

Can somebody please explain me how to arrive to this ans?

Welcome to Gmat Club.

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THEORY.
Permutations of $$n$$ things of which $$P_1$$ are alike of one kind, $$P_2$$ are alike of second kind, $$P_3$$ are alike of third kind ... $$P_r$$ are alike of $$r_{th}$$ kind such that: $$P_1+P_2+P_3+..+P_r=n$$ is:

$$\frac{n!}{P_1!*P_2!*P_3!*...*P_r!}$$.

For example number of permutation of the letters of the word "gmatclub" is $$8!$$ as there are 8 DISTINCT letters in this word.

Number of permutation of the letters of the word "google" is $$\frac{6!}{2!2!}$$, as there are 6 letters out of which "g" and "o" are represented twice.

Number of permutation of 9 balls out of which 4 are red, 3 green and 2 blue, would be $$\frac{9!}{4!3!2!}$$.

So, # of arrangements of a nickel, a dime, and 2 quarters, or arrangements of 4 letters NDQQ out of which 2 Q's appear twice will be $$\frac{4!}{2!}$$. Next, as nickel can face either heads up or tails up then we should multiple this number by 2, so finally we'll get: $$\frac{4!}{2!}*2$$.

Hope it's clear.
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Kudos [?]: 135275 [3], given: 12679

Manager
Status: Still Struggling
Joined: 03 Nov 2010
Posts: 132

Kudos [?]: 106 [0], given: 8

Location: India
GMAT Date: 10-15-2011
GPA: 3.71
WE: Information Technology (Computer Software)
Re: A nickel, a dime, and 2 quarters [#permalink]

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03 Nov 2010, 11:31
thanks a lot...
cleared the concept quite well!!
_________________

Knewton Free Test 10/03 - 710 (49/37)
Princeton Free Test 10/08 - 610 (44/31)
Kaplan Test 1- 10/10 - 630
Veritas Prep- 10/11 - 630 (42/37)
MGMAT 1 - 10/12 - 680 (45/34)

Kudos [?]: 106 [0], given: 8

Intern
Joined: 30 Jun 2015
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Re: A nickel, a dime, and 2 quarters are arranged along a side [#permalink]

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13 Sep 2015, 10:56
shouldnt it be HTHH or HHHH, so 4!/3! +1 = 5

Kudos [?]: 1 [0], given: 2

Math Expert
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Posts: 42544

Kudos [?]: 135275 [0], given: 12679

Re: A nickel, a dime, and 2 quarters are arranged along a side [#permalink]

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14 Sep 2015, 05:27
SahilKataria wrote:
shouldnt it be HTHH or HHHH, so 4!/3! +1 = 5

The number of arrangements of a nickel, a dime, and 2 quarters, or arrangements of 4 letters NDQQ out of which 2 Q's appear twice will be $$\frac{4!}{2!}$$. Next, as nickel can face either heads up or tails up then we should multiple this number by 2, so finally we'll get: $$\frac{4!}{2!}*2$$.
_________________

Kudos [?]: 135275 [0], given: 12679

Intern
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Re: A nickel, a dime, and 2 quarters are arranged along a side [#permalink]

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14 Sep 2015, 11:19
1
KUDOS
i get ur point,
its like nickel head ort tale or a dime head or a tail, not just a head or a tail ...so definitely more than 5 cases.
Apreciate help, Thank u.

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Re: A nickel, a dime, and 2 quarters are arranged along a side [#permalink]

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17 Dec 2016, 08:24
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Re: A nickel, a dime, and 2 quarters are arranged along a side   [#permalink] 17 Dec 2016, 08:24
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