liftoff wrote:
I got B... Used the long approach
List multiples of 36
Add 53 to them and compare result to answers
liftoff wrote:
I got B... Used the long approach
List multiples of 36
Add 53 to them and compare result to answers
thisiszico2006 wrote:
Answer is B , but is there a generic formula or approach for this kind of problem instead of trail and error approach ?
U need to have an approach to solve this. Lets solve this logiccally
Here is the Approach
Given that N=36k+23 Here k could be either odd or even.
we got to find the reminder when 36 multiplied by a number, is divided by 72. So in the above equation K could be of odd or even numbers. give k values starting from 0 to 4
Case 1. When k=0 (36*0)+23 /72 gives reminder 23
Case 2. when k=1 (36*1)+23 /72 gives reminder 59.How we got59 is that-36/72gives reminder36.This 36+ 23=59. )
Case 3.when k= 2 (36*2)+23 /72 gives reminder 23
Case 4.When k=3 (36*3)+23 /72 gives reminder 59
So from this it can be understood that reminder can be either 23 or 59 based on the value of k if its even or odd.
In the choice only 59 is given.
So the answer is B 59 BINGO!!