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A pool can be filled in 4 hours and drained in 5 hours. The

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Re: A pool can be filled in 4 hours and drained in 5 hours. The  [#permalink]

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22 Aug 2015, 19:05
pool can be filled in 4 hours and drained 5 hours.
take lcm of two pipes that is 20 units.
takes 20 hours to fill pool if both the pipes opened simultaneously.

filling pipe can fill 5units/hour.

draing pipe take out 4units?hour.
pool was opened at 1 pm.
pool was filled at 11 pm. It takes 10 hours to complete it.

If drain pipe opened at 2 pm. filling pipe worked for 1 hour. so 5units work over.
remaining 15 units take additional 15 hours to fill.
if drain pipe opened at 2.30pm. filling pipe worked for 1 and 1/2 hour 7.5 units work over.
take 12. 5 units , take additional 12.5 hours to fill.
if drain pipe opened at 3 pm, 10 units units, over, 10 hours to fill.
if drain pipe opened at 3.30pm. 12.5 units over, another 7.5 units , hours take to fill.
3.30+7.30= 11pm
so option D is correct
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26 Aug 2015, 08:09
10/4 - x/5 = 1 not 1/10
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A pool can be filled in 4 hours and drained in 5 hours. The  [#permalink]

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25 Nov 2015, 03:52
1
Economist wrote:
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A pool can be filled in 4 hours and drained in 5 hours. The valve that fills the pool was opened at 1:00 pm and some time later the drain that empties the pool was also opened. If the pool was filled by 11:00 pm and not earlier, when was the drain opened?

A. at 2:00 pm
B. at 2:30 pm
C. at 3:00 pm
D. at 3:30 pm
E. at 4:00 pm

I did:
10/4 - x/5 = 1/10 ( x = number of hours drain pipe is opened ). But I cant find the answer.

m20 q32

I would rather use here smart numbers....
Pool Capacity = 100 Liters
Filling Rate (F) = $$\frac{100}{4}=25$$
Draining Rate (D) = $$\frac{100}{5}=20$$
Time =10 Hours (Start 1:00 pm End 11:00 pm)

250 Liters were filled in 10 hours --> 10*Rate(F) so we have +150 Liters that must be drained (because the filled pool must have only 100 Liters)
$$Rate (D) * t = 150$$ --> $$20*t=150$$, $$t=7.5 Hours$$
Answer D (11 pm - 7.5 =3:30)

Hope this approach helps....
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Re: A pool can be filled in 4 hours and drained in 5 hours. The  [#permalink]

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26 Mar 2018, 09:42
Bunuel

If the value was open for x hours, then why is it (11-1-x) hours when both the valve and the drain were open and not just (11−x)hours?

Thanks!
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26 Mar 2018, 09:49
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mahrah wrote:
Bunuel

If the value was open for x hours, then why is it (11-1-x) hours when both the valve and the drain were open and not just (11−x)hours?

Thanks!

The valve was opened from 1:00 pm to 11:00 pm, so for 11 - 1 = 10 hours. If x is the amount of time when only the valve was open, then 10 - x is the amount of time when both the valve and the drain were open.
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26 Mar 2018, 10:11
Economist wrote:
A pool can be filled in 4 hours and drained in 5 hours. The valve that fills the pool was opened at 1:00 pm and some time later the drain that empties the pool was also opened. If the pool was filled by 11:00 pm and not earlier, when was the drain opened?

A. at 2:00 pm
B. at 2:30 pm
C. at 3:00 pm
D. at 3:30 pm
E. at 4:00 pm

let d=hours drain open
10*1/4-d*1/5=1
d=7.5 hours
11:00 pm-7.5 hours=3:30 pm
D
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Re: A pool can be filled in 4 hours and drained in 5 hours. The  [#permalink]

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28 Mar 2018, 01:51
1

Solution

Given:
• The pool can be filled in 4 hours
• The pool can be drained in 5 hours.
• Filling valve was opened at 1:00 pm
• The Pool was filled at 11:00 pm

Working out:

We need to find out the time when the drain valve was opened.

Per our conceptual knowledge, we know that the total volume of the pool can be taken as the LCM of 4 and 5.
Thus, let’s assume that the total volume of the pool = 20 Liters.

Since the pool can be filled in 4 hours, in 1 hour, the amount of water filled in it = 5 litres.
Similarly, the amount of water drained in 1 hour = 4 litres.

Let’s also assume that the time after which the drain valve was opened = x hours.
So, from 1 pm to (1+x) pm, the pool was being filled at the rate of 5 liters per hour.
And from (1+x) pm to 11 pm, the pool was filled at a rate of (5-4) = 1 liter per hour.

Thus,
• 5*x+ 1(10-x) = 20
• Or, 5x + 10 -x = 20
• Or, 4x = 10
• Or, x =2.5 hours.

Thus, the drain valve was opened at 1+ 2:30 hours = 3:30 pm.

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Re: A pool can be filled in 4 hours and drained in 5 hours. The  [#permalink]

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31 Jul 2019, 19:38
Economist wrote:
A pool can be filled in 4 hours and drained in 5 hours. The valve that fills the pool was opened at 1:00 pm and some time later the drain that empties the pool was also opened. If the pool was filled by 11:00 pm and not earlier, when was the drain opened?

A. at 2:00 pm
B. at 2:30 pm
C. at 3:00 pm
D. at 3:30 pm
E. at 4:00 pm

I did:
10/4 - x/5 = 1/10 ( x = number of hours drain pipe is opened ). But I cant find the answer.

m20 q32

Quick Method

Let the whole pool unit be 5 X 4 = 20
Filling per hour is 5
Draining per hour is 4

Pool was for sure filling from 1 PM to 11 PM which are 10 hours

So, filling pipe started for 10 hours
Work done by Filling Pipe = 50

Equation would be : 50 [Filling pipe ran for 10 hours 5 x 10 ] - 4x [ Draining pipe ran for some hours ] = 20 [ both need to reach this much unit of pool ]
Solving equation x = 7.5 [ Means Draining pipe ran for 7.5 hours out of 10 hours of filling operation ]

Therefore , it should have started after 2.5 hours

Hens Ans is 3:30 PM
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Re: A pool can be filled in 4 hours and drained in 5 hours. The  [#permalink]

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03 Aug 2019, 03:15
Let the capacity be 100 litres

Filling rate-20/hr
draining rate: -25 /hr

Filling pipe worked for 10 hours
Thus, 25*10=250
But, capacity is 100

150 must be drained by draining pipe
Thus, it will take 150/20=7.5 hours to drain

Thus, it has started 2.5 hours after 1 pm

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A pool can be filled in 4 hours and drained in 5 hours. The  [#permalink]

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03 Aug 2019, 16:25
Economist wrote:
A pool can be filled in 4 hours and drained in 5 hours. The valve that fills the pool was opened at 1:00 pm and some time later the drain that empties the pool was also opened. If the pool was filled by 11:00 pm and not earlier, when was the drain opened?

A. at 2:00 pm
B. at 2:30 pm
C. at 3:00 pm
D. at 3:30 pm
E. at 4:00 pm

in 10 hours with drain closed, valve can fill 10/4, or 2.5 pools
so in 10 hours with valve open, drain must empty 2.5-1=1.5 pools
1.5 pools*5 hours=7.5 hours drain needs to leave pool filled at 11:00pm
11:00pm-7.5 hours=3:30pm
D
A pool can be filled in 4 hours and drained in 5 hours. The   [#permalink] 03 Aug 2019, 16:25

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