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# A portion of $6600 is invested at a 5% annual return, while  post reply Question banks Downloads My Bookmarks Reviews Important topics Author Message Senior Manager Joined: 30 Aug 2003 Posts: 322 Location: dallas , tx Followers: 1 Kudos [?]: 27 [0], given: 0 A portion of$6600 is invested at a 5% annual return, while [#permalink]

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15 Dec 2003, 12:27
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A portion of $6600 is invested at a 5% annual return, while the remainder is invested at a 3% annual return. If the annual income from the portion earning a 5% return is twice that of the other portion, what is the total income from the two investments after one year? (A)$180
(B) $270 (C)$300
(D) $320 (E)$360

any shortcuts??
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shubhangi

Manager
Joined: 26 Aug 2003
Posts: 233
Location: United States
Followers: 1

Kudos [?]: 13 [0], given: 0

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15 Dec 2003, 12:55
x = portion invested at 5%

0.05x = 2(0.03(6600 - x))
0.05x = 396 - 0.06x
x = 3600

Return on portion invested at 5% = 0.05(3600) = 180, so the rest of the portion should return 90.

Total return income = 180 + 90 = 270

You can do trial and error methold to get the values too but that may take longer... well depends. To me this theoretical approach was faster. Less than a minute.
15 Dec 2003, 12:55
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