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# A pump started filling an empty pool with water and continue

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Manager
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A pump started filling an empty pool with water and continue [#permalink]

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20 Nov 2008, 11:30
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A pump started filling an empty pool with water and continued at a constant rate until the pool was full. At noon the pool was 1/3 full, and $$1\frac{1}{4}$$ hours later it was 3/4 full. What was the total number of hours that it took the pump to fill the pool?

A. $$2\frac{1}{3}$$
B. $$2\frac{2}{3}$$
C. 3
D. $$3\frac{1}{2}$$
E. $$3\frac{2}{3}$$
[Reveal] Spoiler: OA

Last edited by Bunuel on 11 Apr 2014, 03:29, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.

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20 Nov 2008, 23:18
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Jcpenny wrote:
A pump started filling an empty pool with water and continued at
a constant rate until the pool was full. At noon the pool was 1/3 full,
and 1+1/4 hours later it was 3/4 full. What was the total number of
hours that it took the pump to fill the pool?
A. 2+1/3 B. 2+2/3 C. 3
D. 3+1/2 E. 3+2/3

in 1+1/4 =5/4 hrs the pump filled 3/4-1/3 = 5/12th of the pool
in 1 hr it fills 1/3 of the pool
so in 3 hrs it will fill the entire pool.

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10 Apr 2014, 17:22
alpha_plus_gamma wrote:
Jcpenny wrote:
A pump started filling an empty pool with water and continued at
a constant rate until the pool was full. At noon the pool was 1/3 full,
and 1+1/4 hours later it was 3/4 full. What was the total number of
hours that it took the pump to fill the pool?
A. 2+1/3 B. 2+2/3 C. 3
D. 3+1/2 E. 3+2/3

in 1+1/4 =5/4 hrs the pump filled 3/4-1/3 = 5/12th of the pool
in 1 hr it fills 1/3 of the pool
so in 3 hrs it will fill the entire pool.

I was with you up until 5/12th of the pool. How did you get the in 1 hour it fills 1/3 of the poor?

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Re: A pump started filling an empty pool with water and [#permalink]

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10 Apr 2014, 20:13
Expert's post
1
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Jcpenny wrote:
A pump started filling an empty pool with water and continued at
a constant rate until the pool was full. At noon the pool was 1/3 full,
and 1+1/4 hours later it was 3/4 full. What was the total number of
hours that it took the pump to fill the pool?
A. 2+1/3 B. 2+2/3 C. 3
D. 3+1/2 E. 3+2/3

The time elapsed between 1/3 full pool and 3/4 full pool is 5/4 hrs. This means 3/4 - 1/3 = 5/12 of the pool was filled in 5/4 hrs.

Again, (5/12)th of the pool will be filled in 5/4 hrs

1 pool will be filled in $$\frac{5/4}{5/12} * 1 = 3$$ hrs
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Veritas Prep | GMAT Instructor
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Kudos [?]: 17782 [0], given: 235 Non-Human User Joined: 09 Sep 2013 Posts: 15704 Kudos [?]: 282 [0], given: 0 Re: A pump started filling an empty pool with water and continue [#permalink] ### Show Tags 12 Apr 2015, 22:07 Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________ Kudos [?]: 282 [0], given: 0 Manager Status: I am not a product of my circumstances. I am a product of my decisions Joined: 20 Jan 2013 Posts: 131 Kudos [?]: 122 [1], given: 68 Location: India Concentration: Operations, General Management GPA: 3.92 WE: Operations (Energy and Utilities) A pump started filling an empty pool with water and continue [#permalink] ### Show Tags 02 Jun 2015, 07:04 1 This post received KUDOS Jcpenny wrote: A pump started filling an empty pool with water and continued at a constant rate until the pool was full. At noon the pool was 1/3 full, and $$1\frac{1}{4}$$ hours later it was 3/4 full. What was the total number of hours that it took the pump to fill the pool? A. $$2\frac{1}{3}$$ B. $$2\frac{2}{3}$$ C. 3 D. $$3\frac{1}{2}$$ E. $$3\frac{2}{3}$$ Taking a smart number. Let the capacity of the pool be 12 Liters At 12 PM = $$\frac{1}{3}*12$$ = 4 Liters of water was in the pool. After $$1\frac{1}{4}$$ Hours i.e. at 13:15 Hrs = $$\frac{3}{4}*12$$ = 9 liters of water was in the pool. So in 75 mins the pump fills 9-4 = 5 liters of water in the pool. setting up ratio and proportion $$\frac{X}{75}=\frac{12}{5}$$ $$X = 180 mins = 3 Hours$$ Answer is C Kudos [?]: 122 [1], given: 68 SVP Joined: 06 Nov 2014 Posts: 1905 Kudos [?]: 540 [0], given: 23 Re: A pump started filling an empty pool with water and continue [#permalink] ### Show Tags 02 Jun 2015, 08:54 Expert's post 1 This post was BOOKMARKED A pump started filling an empty pool with water and continued at a constant rate until the pool was full. At noon the pool was 1/3 full, and 1 1/4 hours later it was 3/4 full. What was the total number of hours that it took the pump to fill the pool? (3/4) - (1/3) = 5/12. 5/12 of the pool was full in 1 1/4 hours time (5/4 hours). To determine a rate of filling we divide how much is full by the time. That is (5/12) ÷ (5/4) = 1/3. This means it fills a pool in 3 hours. A. 2 1/3 B. 2 2/3 C. 3 D. 3 1/2 E. 3 2/3 _________________ # Janielle Williams Customer Support Special Offer:$80-100/hr. Online Private Tutoring
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Re: A pump started filling an empty pool with water and continue [#permalink]

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24 Sep 2016, 01:59
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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Re: A pump started filling an empty pool with water and continue [#permalink]

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24 Sep 2016, 05:14
at noon or 12:00PM it is filled 1/3 of total, say x = 1/3x
1hour 15 mins later it is 3/4x filled
so amount it filled in 75mins = (3/4)x - (1/3)x
=> 15*12 mins => 3 hours
C is the answer

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Re: A pump started filling an empty pool with water and continue [#permalink]

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16 Mar 2017, 10:46
OptimusPrepJanielle wrote:
A pump started filling an empty pool with water and continued at a constant rate until the pool was full. At noon the pool was 1/3 full, and 1 1/4 hours later it was 3/4 full. What was the total number of hours that it took the pump to fill the pool?

(3/4) - (1/3) = 5/12. 5/12 of the pool was full in 1 1/4 hours time (5/4 hours). To determine a rate of filling we divide how much is full by the time. That is (5/12) ÷ (5/4) = 1/3. This means it fills a pool in 3 hours.

A. 2 1/3
B. 2 2/3
C. 3
D. 3 1/2
E. 3 2/3

I got as far as finding 5/12- though where are you getting 3 hours? Is it the reciprocal of 1/3?

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Re: A pump started filling an empty pool with water and continue [#permalink]

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17 Mar 2017, 03:34
let the total volume be x and rate of flow be r

3x/4 - x/3 = r *5/4
or 5x/12 = r*5/4
or x = r*3

therefre in three hours, the pool will be filled

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Re: A pump started filling an empty pool with water and continue [#permalink]

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21 Mar 2017, 06:22
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Expert's post
Jcpenny wrote:
A pump started filling an empty pool with water and continued at a constant rate until the pool was full. At noon the pool was 1/3 full, and $$1\frac{1}{4}$$ hours later it was 3/4 full. What was the total number of hours that it took the pump to fill the pool?

A. $$2\frac{1}{3}$$
B. $$2\frac{2}{3}$$
C. 3
D. $$3\frac{1}{2}$$
E. $$3\frac{2}{3}$$

Since it took 1¼ = 5/4 hours to fill 3/4 - 1/3 = 9/12 - 4/12 = 5/12 of the pool, we can let x = the number of hours to fill the pool and create a proportion to determine how long it will take to fill the entire pool.

(5/4)/(5/12) = x/1

5/4 = 5x/12

60 = 20x

x = 3

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Re: A pump started filling an empty pool with water and continue   [#permalink] 21 Mar 2017, 06:22
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