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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]
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I must be totally blind! I do not see how you can get 1.4 hours out of 50/29.

Here's how I see it: each hour 29/50 of the job is completed, therefore after the first hour, 29/50 is complete and 21/50 is still remaining to be completed. 21/50 is just slightly less than 29/50, which is inline with the 1.7 that Juaz got.

Can someone please explain what I am missing? :oops:

Thanks!
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]
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Bluebird wrote:
I must be totally blind! I do not see how you can get 1.4 hours out of 50/29.

Here's how I see it: each hour 29/50 of the job is completed, therefore after the first hour, 29/50 is complete and 21/50 is still remaining to be completed. 21/50 is just slightly less than 29/50, which is inline with the 1.7 that Juaz got.

Can someone please explain what I am missing? :oops:

Thanks!


50/29 = 1.7 hrs

(.7)60 = approx 40 mins

so total time = 1 hour and 40 mins.

I think the answers are a bit confusing.
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]
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lucyqin wrote:
chengliu wrote:
Hey guys can someone please explain to me the explanation below?? Its late and i just dont understand how 50/29 = 1:44 ???

A qualified worker digs a well in 5 hours. He invites 2 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?


* 1:24
* 1:34
* 1:44
* 1:54
* 2:14

R= 1/5 + 2*(3/4)*(1/5)+2*(1/5)*(1/5)= 58/100
T=100/58 or 50/29

So, T= 50/29 or 1:44.
The correct answer is C.


The unit for T is in hours. T=50/29 means 1 hour and 21/29 of an hour which equals 44 minutes.


Is there a fast way of calculating the time 44 mims from 21/29 hours ??
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]
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21/29 is slightly greater (~1/30) than 21/30 or 42/60 or 42 mins.
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]
bunuel,
Is there a method( text book approach) to calculate the time 44 mims from 21/29 hours ??
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]
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Sachin9 wrote:
bunuel,
Is there a method( text book approach) to calculate the time 44 mims from 21/29 hours ??


21/29 th of an hour is (21/29) * (60 minutes) = ~43 minutes.

Walker gave perfect way to get approximate result here: gmat-club-test-m00-64356.html#p470808
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]
A qualified worker digs a well in 5 hours. He invites 2 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?

A) 1:24
B) 1:34
C) 1:44
D) 1:54
E) 2:14



I started with the original rate for the worker as 1/5.

Each apprentice would have a rate (1/5)*(3/4) = 3/20

Each trainee would have a rate (1/5) * (1/5) = 1/25

Combining all of it together 1/5 + 3/20 + 3/20 + 1/25 + 1/25 = 58/100 per hour

After one hour, the remaining work to be done is 42/100

Is it possible to use this approach to solve the problem?
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]
I did just like you and have the same doubt.. If someone could help. :)

undecidedonmba wrote:
A qualified worker digs a well in 5 hours. He invites 2 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?

A) 1:24
B) 1:34
C) 1:44
D) 1:54
E) 2:14



I started with the original rate for the worker as 1/5.

Each apprentice would have a rate (1/5)*(3/4) = 3/20

Each trainee would have a rate (1/5) * (1/5) = 1/25

Combining all of it together 1/5 + 3/20 + 3/20 + 1/25 + 1/25 = 58/100 per hour

After one hour, the remaining work to be done is 42/100

Is it possible to use this approach to solve the problem?
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]
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mestrec wrote:
I did just like you and have the same doubt.. If someone could help. :)

undecidedonmba wrote:
A qualified worker digs a well in 5 hours. He invites 2 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?

A) 1:24
B) 1:34
C) 1:44
D) 1:54
E) 2:14



I started with the original rate for the worker as 1/5.

Each apprentice would have a rate (1/5)*(3/4) = 3/20

Each trainee would have a rate (1/5) * (1/5) = 1/25

Combining all of it together 1/5 + 3/20 + 3/20 + 1/25 + 1/25 = 58/100 per hour

After one hour, the remaining work to be done is 42/100

Is it possible to use this approach to solve the problem?


Hi,
the method is perfect, it only misses out on last step..

what you are getting 58/100 is one hour work..
so the time required will be reciprocal of this=100/58= 1 42/58, which approx equal to 1:44..
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]
Tks for your reply!

We need to do this because of the formula: R x T = J ?

So:
(29/50) x t = 1
t = 1 / (29/50)
t = 50/29

Thats it? :)

Regards.

chetan2u wrote:
mestrec wrote:
I did just like you and have the same doubt.. If someone could help. :)

undecidedonmba wrote:
A qualified worker digs a well in 5 hours. He invites 2 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?

A) 1:24
B) 1:34
C) 1:44
D) 1:54
E) 2:14



I started with the original rate for the worker as 1/5.

Each apprentice would have a rate (1/5)*(3/4) = 3/20

Each trainee would have a rate (1/5) * (1/5) = 1/25

Combining all of it together 1/5 + 3/20 + 3/20 + 1/25 + 1/25 = 58/100 per hour

After one hour, the remaining work to be done is 42/100

Is it possible to use this approach to solve the problem?


Hi,
the method is perfect, it only misses out on last step..

what you are getting 58/100 is one hour work..
so the time required will be reciprocal of this=100/58= 1 42/58, which approx equal to 1:44..
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]
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mestrec wrote:
Tks for your reply!

We need to do this because of the formula: R x T = J ?

So:
(29/50) x t = 1
t = 1 / (29/50)
t = 50/29

Thats it? :)

Regards.

chetan2u wrote:

Hi,
the method is perfect, it only misses out on last step..

what you are getting 58/100 is one hour work..
so the time required will be reciprocal of this=100/58= 1 42/58, which approx equal to 1:44..


Yes, you are absolutely correct with your observation..
Moreover most of the Qs related to this aspect follow these steps..
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Re: A qualified worker digs a well in 5 hours. He invites 2 appr [#permalink]
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Hi All,

These types of 'Work' questions can be solved in a couple of different ways (depending on how you want to 'organize' the rate information). It can often help to think in terms of the number of worker-hours required to complete the job.

The Qualified Worker takes 5 hours to complete a job, so the job requires 5 Worker-hours of effort to be finished.

The Qualified Worker can complete 1 Worker-hour per hour.
Each of the two apprentices can complete 3/4 of a Worker-hour per hour.
Each of the two trainees can complete 1/5 of a Worker-hour per hour.

Total = 1 + 2(3/4) + 2(1/5) = 1 + 1.5 + .4 = 2.9 Worker-hours completed per hour by this group.

Since the job requires 5 Worker-hours of effort, the total time will be...

5/2.9 hours =
50/29 hours =
1 21/29 hours

21/29 is a little more than 2/3 (since 20/30 = 2/3). Thus, we're looking for an answer that is a little more than 1 2/3 hours. There's only one answer that matches....

Final Answer:

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